Answer:
Explanation:
No external force is acting on uranium nucleus so we can apply law of conservation of momentum . If M and m be the mass of bigger and smaller fragments respectively and V and v be their velocity after fission , Total momentum after fission = total momentum before fission
MV - mv = 0 , since the nucleus was at rest , its momentum before fission is zero . negative sign of mv is taken because smaller fragment will move in opposite direction to that of bigger fragment .
MV = mv
M / m = v / V
M > m
Hence,
v > V
So velocity of smaller fragment will be higher .
We're going to remedy it with the parallelogram law.
= one hundred eighty - 30 - 70 = eighty degrees
R = sqrt(2^2 + 3^2 - 2(2)(three) cos(80)
R = three.30 kN, we can conclude now that the value of the ensuing of R is 3.30 kN
sin
/3 = sin(eighty)/three.304 = 63.4 stages
3.3 kN
180 + 33.4 = 213.4 degrees
63.4 - 30 = 33.4
Answer:
Work done, W = 0 J
Explanation:
It is given that,
Weight of the bucket, W = F = 35 N
It is lifted vertically 3 m and then returned to its original position. We need to find the work gravity do on the bucket during this process.
Work done when the bucket is lifted vertically, W₁ = -mgh
Work done when the bucket returned to its original position, W₂ = +mgh
Net work done, W = W₁ + W₂
W = 0 J
So, the work done on the bucket is zero. Hence, this is the required solution.
Let’s come back to the equation of SPEED OF AN ECHO
SPEED =2XDISTANCE/ TIME
So 337*7/2=1179.5 nearest meter =1800 m away
Hope you will get it right