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3 years ago

Jonny tries to ride his bike a little longer each time. Which principle of fitness is he following?

Physics

2 answers:

Volgvan3 years ago

7 0

Answer:

C. Progression

Explanation:

ElenaW [278]3 years ago

3 0

Answer:

Progression

Explanation:

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. The artificial sweetener NutraSweet is a chemical called aspartame (C14H18N2O5). What is (a) its molecular mass (in atomic mas

loris [4]

The molecular mass, in atomic mass unit, of aspartame would be 294 amu while the mass, in kg, of an aspartame molecule would be 0.294 kg

Aspartame has the chemical formula C14H18N2O5

C = 12, H = 1, N = 14, O = 16

(a) Molecular weight = (12x14) + (1x18) + (14x2) + (16x5)

= 168 + 18 + 28 + 80

= 294 amu

(b) Mass of 1 molecule of aspartame = mole x molar mass

= 1 x 294

= 294 g

Converting 294 g to kg = 294/1000

= 0.294 kg

More on mole and molar mass can be found here: brainly.com/question/6613610

7 0

2 years ago

The energy of the electron in Hydrogen atom can be shown to be given by En = -13.6/n^2 eV, where n represents the principal quan

Tpy6a [65]

Answer:

This represents radiation in ultra-violet region .

Explanation:

Energy of the orbit where n = 3 is given as follows

$E_3 =- \frac{13.6 }{3^2}$

$E_3 =- \frac{13.6 }{9}$ = -1.511 eV

Energy of the orbit where n = 1 is given as follows

$E_1 =- \frac{13.6 }{1^2}$

$E_1 =- \frac{13.6 }{1}$ = 13.6 eV

Difference of [tex]E_3 and [tex]E_1 = - 1.511+ 13.6

= 12.089 eV.

The wavelength of light having this energy in nm is given by the expression as follows

Wavelength in nm = 1244 / energy in eV

= 1244 / 12.089

= 102.90 nm

This represents radiation in ultra-violet region .

8 0

3 years ago

A lunar eclipse occurs only when the Moon is new. A lunar eclipse occurs only when the Moon is new. True False

Fittoniya [83]

False. False.

A lunar eclipse occurs only when the moon is full.

A solar eclipse occurs only when the moon is new.

7 0

4 years ago

Answer it answer it answer it

scoray [572]

Answer: I believe the answer is C. Higher Volume.

Explanation: I apologize if I am incorrect.

4 0

3 years ago

The Chernobyl reactor accident in what is now Ukraine was the worst nuclear disaster of all time. Fission products from the reac

Anna35 [415]

Answer:

The correct answer is "53.15 days".

Explanation:

Given that:

Half life of $131_{I}$ ,

$T_{\frac{1}{2} }= 8 \ days$

Let the initial activity be " $R_o$ ".
and, activity to time t be "R".

To find t when R will be "1%" of $R_o$ , then

⇒ $R=\frac{1}{100}R_o$

As we know,

⇒ $R=R_o e^{-\lambda t}$

or,

∴ $e^{\lambda t}=\frac{R_o}{R}$

By putting the values, we get

$=\frac{R_o}{\frac{R}{100} }$

$=100$

We know that,

Decay constant, $\lambda = \frac{ln2}{T_{\frac{1}{2} }}$

hence,

⇒ $\lambda t=ln100$

$t=\frac{ln100}{\lambda}$

$=\frac{ln100}{\frac{ln2}{8} }$

$=53.15 \ days$

5 0

3 years ago