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Sophie [7]
3 years ago
10

you are measuring the mass of various shapes objecys and identifying their shaped ypu then record the qualitative and quanatitav

e data in a table is qualitataive wnd which is quatitaive
Chemistry
1 answer:
tekilochka [14]3 years ago
6 0
Quantitative data is always numerical, like measurements or counts of things. Qualitative data is categorical, like descriptions and names. The type of shape is qualitative, and the mass is quantitative.
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I have no idea how to do this, any help would be appreciated
aksik [14]
Proton number = the atomic number (which is the smaller number
neutron number = the mass number (the bigger number) - the atomic number
number of electrons = the atomic number - the charge (it depends on the element but group 1 is +1 group 2 is +2 group 3 is +3 group five is -3 group six is -2 group seven is -1


i would solve the whole thing but its unclear hope this helps tho
6 0
3 years ago
What mass in grams of SO2 is needed to react with 37.50 mol of Oz?
-BARSIC- [3]

Answer:

4804.5 g of SO₂ are needed to the reaction

Explanation:

The reaction to produce sulfuric acid is:

2SO₂ + O₂ + 2H₂O →  2H₂SO₄

Ratio is 1:2. 1 mol of oxygen needs 2 moles of sulfur dioxide in order to react. We can propose this rule of three.

If 1 mol of O₂ react to 2 moles of SO₂

Then, 37.50 moles of O₂ will react with (37.5 . 2) /1 = 75 moles of SO₂

We convert the moles to mass, to know the answer:

75 mol . 64.06 g / 1 mol = 4804.5 g of SO₂

6 0
3 years ago
What is the electron configuration for La (lanthanum)?
MrRissso [65]

Answer:

Lathanum .

Atomic number = 57

Symbol = La

Atomic weight = 138.9

No of energy orbitals = 6

Electronic configuration

[Xe]6s^25d^1

7 0
3 years ago
Which metal reacts spontaneously with a solution containing zinc ions?
nignag [31]
It would be (1) magnesium.
hope this helps :D
3 0
3 years ago
Read 2 more answers
The radioisotope radon-222 has a half-life of 3.8 days. How much of a 73.9-g sample of radon- (3 222 would be left after approxi
Novay_Z [31]

Answer:

1.115 g

Explanation:

Applying,

R = R'2^{n/t}................... Equation 1

Where R = original sample of radon-222, R' = sample of radon-222 left after decay, n = Total time, t = half-life.

make R' the subject of the equation

R' = R/(2^{n/t})............... Equation 2

From the question,

Given: R = 73.9 g, n = 23 days, t = 3.8 days.

Substitute these values into equation 2

R' = 73.9/(2^{23/3.8})

R' = 73.9/2^{6.05}

R' = 1.115 g

6 0
3 years ago
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