Answer:
Explanation:
1 mole of Fe require 2 Moles of NiO(OH)
so for 4.25 mol of Fe and 6.70 mol of NiO(OH), Fe is the limiting reagent.
1 mole produces 1 mole of Fe(OH)2
4.25 moles will produce 4.25 moles of Fe(OH)2
It is a simple stoichiometry problem. We have been given with balanced equation and 5.00 moles of HCl and have to calculate the moles of H2.
<span>From the balanced equation it is being clear that 2 moles of HCl are produced by 1 mole of H2. so, 1 mole of HCl will be produced by 1/2 moles of H2. So, the mole ratio of H2 and HCl is 1:2 </span>
<span>to calculate the moles of H2 for the given moles of HCl, multiply the moles of HCl by the mole ratio of H2 and HCl. </span>
<span>5.00 mole HCl x (1 mole H2/ 2 mole HCl) </span>
<span>= 2.50 mole H2 </span>
<span>so, to produce 5.00 moles of HCl, 2.50 moles of H2 are required.</span>
Answer:
17.136 g H2
Explanation:
First we need to convert moles of Zinc to moles of Hydrogen in order to find out how many moles of hydrogen are produced.
When we look at our balanced equation, we can see that for every mole of Zn reacting, there is 1 mol of H2 produced. (imagine a 1 in front of the elements that have no numbers in front of them)
8.5 mol Zn * 
= 8.5 mol H2
Now we will convert from moles of Hydrogen to grams
The atomic mass of H2 is 2(1.008) g/1 mol... so we will use this to convert to the number of grams of Hydrogen produced..
8.5 mol H2 * 
= 17.136 g H2
Answer:
Warning means that it is getting smaller while crescent refers to the crurved shape simular to a banana or a boat. The warning crescent moon rises after midnight and is still up and visible in the morning and day sky before itsets in the afternoon.
Explanation:
Answer:
The energy required is 3225 Joules.
Explanation:
Given,
mass of lead cube = 500 grams
T₁ = 25°C
T₂ = 75°C
specific heat of lead = 0.129 J/g°C
Energy required to heat the lead can be found by using the formula,
Q = (mass) (ΔT) (Cp)
Here, ΔT = T₂ - T₁ = 75 - 25 = 50
Substituting the values,
Q = (500)(50)(0.129)
Q = 3225 Joules.
Therefore, energy required is 3225 J.
