A nuclide of phosphorus 3015P decays into a nuclide of silicon 3014Si. In order to satisfy charge conservation and lepton number
1 answer:
In order to satisfy charge conservation and lepton number conservation the other products must be neutron.
<h3>What is conservation of mass?</h3>
The principle of conservation of mass states that, the sum of the initial mass of reactants must be equal to final mass of the products.
The balanced reaction of radioactive decay of phosphorous shows conservation of mass.
Thus, in order to satisfy charge conservation and lepton number conservation the other products must be neutron.
Learn more about radioactive decay here: brainly.com/question/1383030
#SPJ1
You might be interested in
Answer:
(a) Increasing the temperature adds heat which is a reactant shifting the equilibrium rightwards.
(b) Pressure has no effect since the change in the number of moles is zero.
Explanation:
Hello,
In this case, one could represent the given reaction as:
Since it is endothermic. Thus, solving the (a) statement, one identifies the heat as a reagent, that is why the reaction cools down as it progress, therefore, by increasing the temperature, heat is added, that is, a reagent is added, which shifts the equilibrium rightwards, in other words, more NO is produced so its concentration increases.
Furthermore, for the (b) statement, since the change in the number of moles is zero, based on the stoichiometric coefficients as shown below:
Such value implies that the pressure has no effect on the concentration, taking into account the following form of the law of mass action:
Thus, since ,
, so no effect in concentration is due to the pressure.
Best regards.