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lbvjy [14]
2 years ago
13

A nuclide of phosphorus 3015P decays into a nuclide of silicon 3014Si. In order to satisfy charge conservation and lepton number

conservation the other products must be __________.
Chemistry
1 answer:
jeka942 years ago
3 0

In order to satisfy charge conservation and lepton number conservation the other products must be neutron.

<h3>What is conservation of mass?</h3>

The principle of conservation of mass states that, the sum of the initial mass of reactants must be equal to final mass of the products.

_{15}^{30}P\ --- > \ _{14}^{30} Si \ + \ ^{0}_{1} n

The balanced reaction of radioactive decay of phosphorous shows conservation of mass.

Thus, in order to satisfy charge conservation and lepton number conservation the other products must be neutron.

Learn more about radioactive decay here: brainly.com/question/1383030

#SPJ1

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A solution is prepared by adding 100 mL of 1.0 M HC₂H₃O₂(aq) to 100 mL of 1.0 M NaC₂H₃O₂(aq). The solution is stirred and its pH
anastassius [24]

Answer: Option (c) is the correct answer.

Explanation:

When an acid or base is added to a solution then any resistance by the solution in changing the pH of the solution is known as a buffer.

This is because a buffer has the ability to not get affected by the addition of small amounts of an acid or a base. As a result, it helps in maintaining the pH of the solution.

In the give case, when we add the HCl then more number of protons will dissociate. This causes the acetate to react with the protons and leads to the formation of acetic acid.

We know that acetic acid is a weak acid and it dissociates partially or feebly. Therefore, no change in pH will take place.

Thus, we can conclude that equation H_{3}O^{+}(aq) + C_{2}H_{3}O^{-}_{2}(aq) \rightarrow HC_{2}H_{3}O_{2}(aq) + H_{2}O(l) represents the chemical reaction that accounts for the fact that acid was added but there was no detectable change in pH.

3 0
3 years ago
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Vesna [10]

Answer:first D. 88L

Second A 2*10^24

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280 g =280/70.9 moles, about 4

4*22.4 = about 88

aw Sr 87.6 —> 6.02214076*10^23 atoms = 1 mole

5 0
3 years ago
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