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Kipish [7]
3 years ago
14

Ronaldo experimentally determined the

Chemistry
1 answer:
Yuri [45]3 years ago
5 0

Answer:

Explanation:

%error= error/actual density x100

0.050/0.890  x100

=5.62%

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Before "true" labor begins, you might have "false" labor pains, also known as Braxton Hicks contractions.

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Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical equation:
Elan Coil [88]

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3

2

Explanation:

3O2 => 2O3

the equation is balancing

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Solve to me this question
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According to my calculations the correct Answer is C. +694. The answers A B and D Are incorrect. It cannot be A because I said it also cannot be B because C=H. The answer would not be D because balls in your jaws = +1192 And the answer will be CORRECT ANSWER C=+694
8 0
3 years ago
Calculate the pH in titration of a weak acid: What is the pH in titration of formic acid (HCHO2, 0.200 M, 100.0 mL) after the ad
ki77a [65]

Answer:

pH = 12.61

Explanation:

First of all, we determine, the milimoles of base:

0.120 M = mmoles / 300 mL

mmoles = 300 mL . 0120 M = 36 mmoles

Now, we determine the milimoles of acid:

0.200 M = mmoles / 100 mL

mmoles = 100 mL . 0.200M = 20 mmoles

This is the neutralization:

HCOOH    +     OH⁻         ⇄        HCOO⁻     +    H₂O

20 mmol       36 mmol             20 mmol

                    16 mmol

We have an excess of OH⁻, the ones from the NaOH and the ones that formed the salt NaHCOO, because this salt has this hydrolisis:

NaHCOO  →  Na⁺  +  HCOO⁻

HCOO⁻  +  H₂O  ⇄   HCOOH  +  OH⁻   Kb →  Kw / Ka = 5.55×10⁻¹¹

These contribution of OH⁻ to the solution is insignificant because the Kb is very small

So:  [OH⁻] =  16 mmol / 400 mL →  0.04 M

- log  [OH⁻]  = pOH →  1.39

pH = 14 - pOH → 12.61

6 0
3 years ago
Which has more particles? 10.0 g of Carbon or 10.0 g Calcium? How many atoms does each have?
Snezhnost [94]

Answer:

10g Carbon has more particles.

Explanation:

To Find

Which has more particles 10g of C or 10g of Ca

The molar mass of carbon is 12g and Calcium is 40g.

1 mole of  atom , molecule or ions contain Avagadro number (6.022×10∧23) of particles and also have a mass equal to it's molar mass.

For C,

12g C  will have 6.022×10∧23 atoms

10g C will have  \frac{10}{12} ×6.022×10∧23 atoms

=0.833 × 10∧23 atoms

For Ca,

1 mole Ca =40g

40g Ca will have 6.022×10∧23 atoms

10g Ca will have \frac{10}{40} ×6.022×10∧23 atoms

=0.25 × 6.022×10∧23 atoms

7 0
3 years ago
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