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Vikentia [17]
3 years ago
7

Which of the following represents a neutralization reaction which hydrofluoric acid and sodium hydroxide(a base) react to produc

e sodium choride(a salt) and water? 
Chemistry
1 answer:
Olenka [21]3 years ago
3 0

Explanation:

A neutralization reaction is a reaction that involves an acid and a base.

When an acid reacts with a base to produce salt and water only, the reaction is said to be a neutralization reaction.

  Acid    +  Base    →  Salt  +  Water

Such reactions are classified as a double displacement reaction in which a non-ionizing product is formed

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A scientist finds one carbon atom for every two oxygen atoms in a sample of compound x. for which other samples of compound x sh
Doss [256]

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3 years ago
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How many number of moles are present in 200. g of sodium bicarbonate (NaHCO3)
nikdorinn [45]

You can solve this problem through dimensional analysis.

First, find the molar mass of NaHCO3.

Na = 22.99 g

H = 1.008 g

C = 12.01 g

O (3) = 16 (3) g

Now, add them all together, you end with with the molar mass of NaHCO3.

22.99 + 1.008 + 12.01 + 16(3) = 84.008 g NaHCO3. This number means that for every mole of NaHCO3, there is 84.008 g NaHCO3. In simpler terms, 1 mole NaHCO3 = 84.008 g NaHCO3.

After finding the molar mass of sodium bicarbonate, now you can use dimensional analysis to solve for the number of moles present in 200. g of sodium bicarbonate.

200. g NaHCO_3 * \frac{1 mole NaHCO_3}{84.008 g NaHCO_3}

Cross out the repeating units which are g NaHCO3, and the remaining unit is mole NaHCO3

200.  * 1 = 200

200/ 84.008 = 2.38

Notice how there are only 3 sig figs in the answer. This is because the given problem only gave three sig figs.

Your final answer is 2.38 mol NaHCO3.

8 0
3 years ago
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a molecule containing a very large number of atoms, such as a protein, nucleic acid, or synthetic polymer.

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</span><span><span>H^+<span>H<span><span>​+</span><span>​​</span></span></span></span>H, start superscript, plus, end superscript</span><span> ions from the splitting of water also add to the gradient.
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