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nikdorinn [45]
3 years ago
6

The sun warming the surface of a rock is conduction convection radiation

Chemistry
2 answers:
Sindrei [870]3 years ago
7 0
Radiation..................
horsena [70]3 years ago
7 0
Radiation is your answer...
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when 6.25 grams of pure iron are allowed to react with oxygen , a black oxide forms. if the product weighs 8.15 g, what is the e
erik [133]
We are given with the mass of  pure iron that reacts with oxygen to form an oxide which has a given mass as well. the mass of oxygen reacted is 8.15-6.25 g or 1.9 grams. THen we convert the mass of the reactants to moles. Iron is equal to 0.1119 moles and oxygen is equal to 0.1188. We divide each number to the less amount. Hence iron is 1 and oxygen is approx 1. The empirical formula hence is FeO or ferrous oxide or Iron (II) oxide.
5 0
3 years ago
Equation for questions 1-4:
Karolina [17]

Answer:

5.625 moles of oxygen, O₂.

Explanation:

The balanced equation for the reaction is given below:

4Al + 3O₂ —> 2Al₂O₃

From the balanced equation above,

4 moles of Al reacted with 3 moles of O₂.

Finally, we shall determine the number of mole of O₂ required to react with 7.5 moles of aluminum, Al. This can be obtained as illustrated below:

From the balanced equation above,

4 moles of Al reacted with 3 moles of O₂.

Therefore, 7.5 moles of Al will react with = (7.5 × 3)/4 = 5.625 moles of O₂.

Thus, 5.625 moles of O₂ is needed for the reaction.

3 0
3 years ago
What action would you expect an atom of Aluminum to undergo?
KATRIN_1 [288]

Answer:

C. Lose three electrons to have a full outer shell  

Explanation:

Al is in Group 13 of the Periodic Table, so it has three valence electrons.

It must either lose three electrons or gain five to achieve a stable octet.

It is easier to lose three electrons than it is to gain five, so Al loses three electrons.

D. is wrong, for the same reason.

A. is wrong. If Al lost three electrons, it would be breaking into a stable inner shell.

C. is wrong. Al is a metal, so it will lose electrons in a reaction.

6 0
3 years ago
Find the percentage composition of a compound that contains 1.94 g of carbon, 0.48 g of hydrogen, and 2.58 g of sulfur.
Svetradugi [14.3K]

Answer : The percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

Explanation :

To calculate the percentage composition of element in sample, we use the equation:

\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100

Given:

Mass of carbon = 1.94 g

Mass of hydrogen = 0.48 g

Mass of sulfur = 2.58 g

First we have to calculate the mass of sample.

Mass of sample = Mass of carbon + Mass of hydrogen + Mass of sulfur

Mass of sample = 1.94 + 0.48 + 2.58 = 5.0 g

Now we have to calculate the percentage composition of a compound.

\%\text{ composition of carbon}=\frac{1.94g}{5.0g}\times 100=38.8\%

\%\text{ composition of hydrogen}=\frac{0.48g}{5.0g}\times 100=9.6\%

\%\text{ composition of sulfur}=\frac{2.58g}{5.0g}\times 100=51.6\%

Hence, the percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

3 0
3 years ago
Anyone could help me out?
Hoochie [10]

1.4 mg/dL = 0.014 g/L

Explanation:

Milligrams per deciliter to grams per liter

There is 1000 grams of mg/dL of 1 g/L

8 0
3 years ago
Read 2 more answers
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