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4 years ago

Please help ill medal and fan!

1 answer:

6 0

Solutions for your questions are the following:
1. remaining amount is equal to:960 g : 100% = 30 g : xx = 30 g * 100% / 960 g
= 3.125%
= 0.03125
Now, we use this formula to calculate the number of half-lives:(1/2)ⁿ = x,
so,(1/2)ⁿ = 0.03125
to calculate n, use this equation:
n*log(1/2) = log(0.03125) n = log(0.03125)/log(1/2)
= log(0.03125)/log(0.5)
= -1.505/-0.301
n=5

Ifn = 5T = 15 min

Then
L = T/nL = 15 min/5
= 3 minutes

2. You should pick filtration. It is use to separate heterogeneous mixtures just like in the problem stated.

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WILL MARK BRAINLIEST!!From where does geothermal energy come?

damaskus [11]

Answer:

A)from deep within the earth

Explanation:

5 0

3 years ago

1N2 + 3H2 -->

Hunter-Best [27]

Answer:

28.23 g NH₃

Explanation:

The balanced chemical equation is:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

Thus, 1 mol of N₂ reacts with 2 moles of H₂ to produce 2 moles of NH₃. We convert the moles to mass (in grams) by using the molecular weight (MW) of each compound:

MW(N₂) = 2 x 14 g/mol = 28 g/mol

mass N₂= 1 mol x 28 g/mol = 28 g

MW(H₂) = 2 x 1 g/mol = 2 g/mol

mass H₂ = 3 mol x 2 g/mol = 6 g

MW(NH₃) = 14 g/mol + (3 x 1 g/mol) = 17 g/mol

mass NH₃= 2 moles x 17 g/mol = 34 g

Now, we have to figure out which is the limiting reactant. For this, we know that the stoichiometric ratio is 28 g N₂/6 g H₂. If we have 36.85 g of H₂, we need the following mass of N₂:

36.85 g H₂ x 28 g N₂/6 g H₂ = 171.97 g N₂

We have 23.15 g N₂ and we need 171.97 g. So, we have lesser N₂ than we need. Thus, the limiting reactant is N₂.

Now, we calculate the product (NH₃) by using the stoichiometric ratio 34 g NH₃/28 g N₂, with the mass of N₂ we have:

23.25 g N₂ x 34 g NH₃/28 g N₂ = 28.23 g NH₃

Therefore, the maximum amount of NH₃ that can be produced is 28.23 grams.

5 0

3 years ago

Which of the following is an example of a biological polymer?

katrin2010 [14]

A) polyester, hope it was quick enough

4 0

3 years ago

Use the table on the right to calculate each required quantity

ValentinkaMS [17]

(1) The quantity of heat required to melt 175 g Cu is 35.88 kJ.

(2) The substance that releases 21.2 kJ of energy when 1.42 mol of it freezes is iron.

<h3>What is heat of fusion?</h3>

Heat of fusion is the energy required to melt 1 mole of a substance.

<h3>What is heat of vaporization?</h3>

The heat energy required to vaporize 1 mole of a substance has been heat of vaporization.

Heat of fusion of copper (Cu) is given as 13 kJ/mol

Number of moles of 175 g of copper = 175/63.5 = 2.76 moles

Q = nΔH

Q = 2.76 mol x 13 kJ/mol = 35.88 kJ

Thus, the quantity of heat required to melt 175 g Cu is 35.88 kJ.

<h3>Heat of fusion of the substance</h3>

ΔH(fus) = Q/n

where;

n is number of moles
Q is quantity of heat released

ΔH(fus) = 21.2 kJ / 1.42 mol

ΔH(fus) = 14.93 kJ/mol

From the table the substance with latent heat of fusion of 14.9 kJ/mol is iron.

Thus, the substance that releases 21.2 kJ of energy when 1.42 mol of it freezes is iron.

Learn more heat of fusion here: brainly.com/question/87248

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3 0

2 years ago

Predict the bond present between carbon and hydrogen in polyethylene

sweet-ann [11.9K]

It is an alkene: CnH2n (n=number of the atoms of carbon)
in ethylene there are two carbons so:
C2H4 just like the picture

6 0

4 years ago