4 years ago

Having trouble with the Order Of Operations?

2 answers:

8 0

Great tip!

PEMDAS is important to use because if you don’t, you could possibly get the wrong answer to the equation. Thanks for sharing!

-AaronWiseIsBae

CaHeK987 [17]4 years ago

3 0

I think it’s called bedmas where b is for brackets anyways thanks for the tip

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Please explain how to find the simplest form of 7/28! I did it in 5th grade but forgot! Explain please.

Lapatulllka [165]

$\sf \frac{7}{28} = \frac{7 \times 1}{7\times 4}\\ We~can~divide~by~7~on~both~the~numerator~and~denominator\\\frac{7\times 1\div 7}{7\times 4\div 7} = \frac{1}{4}$

So in simplest form it would be 1/4

6 0

3 years ago

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How do I find ac in this problem

suter [353]

7 / x+4 = 5/x+1 =

5x+20 = 7x+7 =

20=2x+7

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3 years ago

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4 years ago

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If f(x) = 3x + 7, which of these is the inverse of f(x)?

dolphi86 [110]

Answer:

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Step-by-step explanation:

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3 years ago

If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?

aksik [14]

$ab = 8$ & $a^{2} + b^{2} = 16$ so , $( a+b )^{2} = 32$ .

<u>Step-by-step explanation:</u>

Here we have , ab= 8 & a^2+b^2=16 i.e. $ab = 8$ and $a^{2} + b^{2} = 16$ .

We need to find value of (a+b)^2 i.e. $(a+b)^{2}$ :

It's and identity and we know that $( a+b )^{2} = a^{2} +b^{2} +2ab$

⇒ $( a+b )^{2} = a^{2} +b^{2} +2ab$

⇒ $( a+b )^{2} = (a^{2} +b^{2}) +2(ab)$

⇒ $( a+b )^{2} = (16) +2(8)$

⇒ $( a+b )^{2} = (16) +(16)$

⇒ $( a+b )^{2} = 32$

∴ $ab = 8$ & $a^{2} + b^{2} = 16$ so , $( a+b )^{2} = 32$ .

6 0

3 years ago