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3 years ago

Are all negative numbers integers

Mathematics

2 answers:

Tju [1.3M]3 years ago

6 0

Answer: yes

Step-by-step explanation:

unless it is a fraction or a decimal

laiz [17]3 years ago

6 0

Answer:

Step-by-step explanation:

Because a negative number can be both an integer and fraction and a decimal not all negative numbers can be integers because integers can only be whole numbers (both positive and negative).

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Two major cities each have a population of

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Realistically would be 20.

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2 years ago

65% of 51. Please also show me how to do it because I can't.

kvasek [131]

Answer:

Step-by-step explanation:

65% of 51 = $\dfrac{65}{100}*51$

= 0.65 *51

= 33.15

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2 years ago

Please help me with this equation, you are supposed to find x

Lena [83]

Answer:

Step-by-step explanation:

$\frac{3}{4}(x+21) =10\frac{1}{2} \\x+21=14\\x=-7$

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3 years ago

Read 2 more answers

Function f is defined by the equation f (x) = x^2. <br> What is f (3)<br> PLZ HURRY

Alex787 [66]

Answer:

f(3) = 9

Step-by-step explanation:

f(x) = x^2

f(3) means "When x is 3" So, we substitute x with 3.

f(3) = 3^2

f(3) = 3 x 3 = 9

f(3) = 9

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3 years ago

Express the inverse of the following matrix (assuming it exists) as a matrix containing expressions in terms of k.

ale4655 [162]

Answer:

the Inverse of the matrix is; A⁻¹

$= \left[\begin{array}{ccc}\frac{-3}{(2k)} &\frac{1}{k}&\frac{15}{(2k)}\\\frac{-3k+15}{(10k)}&\frac{-1}{k}&\frac{-75+13k}{(10k)}\\\frac{1}{2}&0&\frac{-5}{2}\end{array}\right]$

Step-by-step explanation:

Given the data in the question;

Matrix A = $\left[\begin{array}{ccc}-25&-25&-13\\k&0&3\\-5&-5&-3\end{array}\right]$

To find the Inverse of matrix A

A⁻¹ = Adj.A / det.A

Determinant of the matrix A will be

|A| = -25( 0 + 15) + 25( -3K + 15 ) - 13( -15K + 0 )

= -375 - 75K + 375 + 65K

= -10K

Now, the adjoin of matrix A will be

Adj.A = $\left[\begin{array}{ccc}15&-10&-75\\3k-15&10&75-13k\\-5k&0&25k\end{array}\right]$

The Inverse of the matrix is;

A⁻¹ = Adj.A / det.A

$= \frac{1}{-10k} \left[\begin{array}{ccc}15&-10&-75\\3k-15&10&75-13k\\-5k&0&25k\end{array}\right]$

$= \left[\begin{array}{ccc}\frac{15}{-10k} &\frac{-10}{-10k}&\frac{-75}{-10k}\\\frac{3k-15}{-10k}&\frac{10}{-10k}&\frac{75-13k}{-10k}\\\frac{-5k}{-10k}&\frac{0}{-10k}&\frac{25k}{-10k}\end{array}\right]$

$= \left[\begin{array}{ccc}\frac{-3}{2k} &\frac{1}{k}&\frac{15}{2k}\\\frac{-3k+15}{10k}&\frac{-1}{k}&\frac{-75+13k}{10k}\\\frac{1}{2}&0&\frac{-5}{2}\end{array}\right]$

$= \left[\begin{array}{ccc}\frac{-3}{(2k)} &\frac{1}{k}&\frac{15}{(2k)}\\\frac{-3k+15}{(10k)}&\frac{-1}{k}&\frac{-75+13k}{(10k)}\\\frac{1}{2}&0&\frac{-5}{2}\end{array}\right]$

Therefore the Inverse of the matrix is; A⁻¹

$= \left[\begin{array}{ccc}\frac{-3}{(2k)} &\frac{1}{k}&\frac{15}{(2k)}\\\frac{-3k+15}{(10k)}&\frac{-1}{k}&\frac{-75+13k}{(10k)}\\\frac{1}{2}&0&\frac{-5}{2}\end{array}\right]$

7 0

2 years ago