Answer:
Step-by-step explanation:
Given that , the sum of the first nine terms of an arithmetic series is 162 and the sum of the first 12 terms is 288.
<h3>
<u>Related</u><u> </u><u>Infor</u><u>mation</u><u> </u><u>:</u><u>-</u><u> </u></h3>
• The sum of n terms of an AP is
![\boxed{\orange{\sf S_n = \dfrac{n}{2}[2a+(n-1)d] }}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Corange%7B%5Csf%20S_n%20%3D%20%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D%20%7D%7D)
• nth term of an AP is given by ,
Answer:
2) 4/3
Step-by-step explanation:
(4^-3 * 3^4 * 4^2)/(3^5 * 4^-2)
4^-3 * 3^4 * 4^2 = 4^-1 * 3^4
(4^-1 * 3^4)/(4^-2 * 3^5)
(3^4)/(3^5) = 1/(3^5-4)
(4^(-1))/(4^-2 * 3^(5-4)
(4^-1)/(4^-2 * 3)
4^(-1 - (-2)) / (3)
-1 - (-2) = 1
4/3
-16+-x/4=-3
-x/4=13
-x=52
x=-52
Answer:
14>3
Step-by-step explanation:
you would need to turn the 3 in the parenthesis into a fraction which would result in 9/3. 2/3 - 9/3= -7/3
Multiply the 7/3 by 6 and by what I have always been taught, you only multiply the top of the fraction. This would leave it to be 42/3 which would be known as 14.
So therefore the answer would be 14>3
