3 years ago

Find the equation of the line normal to the curve of y=cos1/3x, where x=pi

Mathematics

1 answer:

miv72 [106K]3 years ago

5 0

Answer:

The equation of the line normal to the curve of y=cos1/3x, where x=pi is y= 2√3 x - 10.38

Step-by-step explanation:

The equation of the normal to the curve is

Y- y1 = - 1/m (x- x1)

Where m is the gradient.

See attached picture for the complete solution.

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guapka [62]

Answer:

$X=\$519.48$

Step-by-step explanation:

From the question we are told that

Loan 1 $X_1=\$400$

Loan 1 due $t_1=95days$

Loan 2 $X_2=\$700$

Loan 2 due $t_2=0days$

Payment $Y=\$600$

Worth of money $w=6\%$

Payment due $t=30days$

Focal date $t_f=125days$

Generally $\$400$ was due 95days ago

Therefore

$125+90=220days$ (total days to consider)

Therefore

$300+400 =700$ is due today

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Given

600 due in 30days

$125-30=95days$

Generally the Final payment is mathematically given by

$400(1+ 0.06*\frac{220}{365} ) + 700(1+0.06*\frac{125}{365} )=600(1+0.06*\frac{95}{365} )+X$

$X=1128.9692 - 609.3698$

Therefore the

$X=\$519.48$

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