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gtnhenbr [62]
3 years ago
10

Car A is traveling at 20.0 m/s and car B at 27.0 m/s.

Physics
1 answer:
Savatey [412]3 years ago
4 0

Take the moment car A starts to accelerate to be the origin. Then car A has position at time <em>t</em>

<em>x</em> = (20.0 m/s) <em>t</em> + 1/2 (2.10 m/s²) <em>t</em>²

and car B's position is given by

<em>x</em> = 300 m + (27.0 m/s) <em>t</em>

<em />

Car A overtakes car B at the moment their positions are equal:

(20.0 m/s) <em>t</em> + 1/2 (2.10 m/s²) <em>t</em>² = 300 m + (27.0 m/s) <em>t</em>

300 m + (7.00 m/s) <em>t</em> - (1.05 m/s²) <em>t</em>² = 0

==>  <em>t</em> ≈ 20.6 s

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7 0
2 years ago
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So, the change in the potential energy is

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