<h2>
The baseball drops by 0.64 meter.</h2>
Explanation:
Consider the horizontal motion of ball
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 44.7 m/s
Acceleration, a = 0 m/s²
Displacement, s = 16.1 m
Substituting
s = ut + 0.5 at²
16.1 = 44.7 x t + 0.5 x 0 x t²
t = 0.36 s
Time taken to travel 16.1 m is 0.36 seconds
Now we need to find how much ball travel vertically during this 0.36 seconds.
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Time, t = 0.36 s
Substituting
s = ut + 0.5 at²
s = 0 x 0.36 + 0.5 x 9.81 x 0.36²
s = 0.64 m
The baseball drops by 0.64 meter.
Answer:
(A) more rapidly than
Explanation:
With higher temperatures, object's molecules (and atoms) have higher kinetic energy which is due to faster "jiggling" (vibrations). On a hot day these vibrations in the material the sidewalk is made of are more rapid than on a cold day, just as their temperatures differ.
since the car moves, the force needed to move is greater than the frictional forces opposing it
a = 3.17m/s²
Answer:
728 N
Explanation:
= length of the wire = 0.680 m
= mass of the steel wire = 0.0046 kg
= Fundamental frequency = 261.6 Hz
= tension force in the steel wire
Fundamental frequency in wire is given as

Answer:
v = 7.67 m/s
Explanation:
The equation for apparent weight in the situation of weightlessness is given as:
Apparent Weight = m(g - a)
where,
Apparent Weight = 360 N
m = mass passenger = 61.2 kg
a = acceleration of roller coaster
g = acceleration due to gravity = 9.8 m/s²
Therefore,
360 N = (61.2 kg)(9.8 m/s² - a)
9.8 m/s² - a = 360 N/61.2 kg
a = 9.8 m/s² - 5.88 m/s²
a = 3.92 m/s²
Since, this acceleration is due to the change in direction of velocity on a circular path. Therefore, it can b represented by centripetal acceleration and its formula is given as:
a = v²/r
where,
a = centripetal acceleration = 3.92 m/s²
v = speed of roller coaster = ?
r = radius of circular rise = 15 m
Therefore,
3.92 m/s² = v²/15 m
v² = (3.92 m.s²)(15 m)
v = √(58.8 m²/s²)
<u>v = 7.67 m/s</u>