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3 years ago

1. Suppose you know that the net force on an object is zero. What can you say about

Physics

1 answer:

Kryger [21]3 years ago

3 0

If the net force on an object is zero, then ...

a). The object's acceleration is zero.

b). The object's velocity is a constant speed in a straight line.

Note: (a) and (b) both say the same thing.

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A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wave

Ann [662]

Answer:

$\lambda$ = 40 cm

Explanation:

given data

string length = 30 cm

solution

we take here equation of length that is

L = $n \times \frac{1}{4} \lambda$ ...............1

total length will be here

$L = \frac{\lambda}{2} + \frac{\lambda}{4}\\$

$L = \frac{3 \lambda }{4}$

so $\lambda$ will be

$\lambda = \frac{4L}{3}\\\lambda = \frac{4\times 30}{3}$

$\lambda$ = 40 cm

5 0

3 years ago

Effects of heat on matter

kumpel [21]

Answer:

it can melt orcan put them past their boiling point

Explanation:

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3 years ago

A charge Q is transferred from an initially uncharged plastic ball to an identical ball 24 cm away.The force of attraction is th

xxMikexx [17]

Answer:

The number of electrons transferred from one ball to the other is 2.06 x 10¹² electrons

Explanation:

Given;

magnitude of the attractive force, F = 17 mN = 0.017 N

distance between the two objects, r = 24 cm = 0.24 m

The attractive force is given by Coulomb's law;

$F = \frac{1}{4\pi \epsilon _0} \times \frac{Q^2}{r^2} = \frac{kQ^2}{r^2} \\\\Q^2 = \frac{Fr^2}{k} \\\\Q = \sqrt{ \frac{Fr^2}{k}} \\\\Q = \sqrt{ \frac{(0.017)(0.24)^2}{9\times 10^9}} \\\\Q = 3.298 \times 10^{-7} \ C$

The charge of 1 electron = 1.602 x 10⁻¹⁹ C

n(1.602 x 10⁻¹⁹ C) = 3.298 x 10⁻⁷

$n = \frac{3.298 \times 10^{-7}}{1.602 \times 10^{-19}} = 2.06 \times 10^{12} \ electrons$

Therefore, the number of electrons transferred from one ball to the other is 2.06 x 10¹² electrons

4 0

3 years ago

Pls help I have to submit it

mihalych1998 [28]

Answer:

Acceleration =

$2 \: ms {}^{ - 2}$

Explanation:

Acceleration =

$\frac{change \: in \: velocity }{time}$

=》

$\frac{21 - 15}{3}$

=》

$\frac{6}{3}$

=》

$2$

hence, acceleration =

$2 \: ms {}^{ - 2}$

7 0

3 years ago

Explain the changes in molecular motion of particles as they change from solid to liquid to gas.

andrey2020 [161]

Answer:

A rise in temperature increases the kinetic energy and speed of particles; it does not weaken the forces between them. The particles in solids vibrate about fixed positions; even at very low temperatures. Individual particles in liquids and gases have no fixed positions and move chaotically.

Explanation:

8 0

3 years ago