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svetoff [14.1K]
2 years ago
9

Tsunamis are fast-moving waves often generated by underwater earthquakes. In the deep ocean their amplitude is barely noticable,

but upon reaching shore, they can rise up to the astonishing height of a six-story building. One tsunami, generated off the Aleutian islands in Alaska, had a wavelength of 646 km and traveled a distance of 3630 km in 6.15 h. (a) What was the speed (in m/s) of the wave
Physics
1 answer:
vovangra [49]2 years ago
6 0

Answer:

v =163.95 m/s

Explanation:

Given that,

The wavelength of wave, \lambda=646\ km=646\times 10^3\ m

Distance covered, d=3630\ km=3630\times 10^3\ m

We need to find the speed of the wave. We know that,

speed = distance/time

So,

v=\dfrac{3630\times 10^3\ m}{22140\ s}\\\\=163.95\ m/s

So, the speed of the wave is equal to 163.95 m/s.

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PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!!
gladu [14]

Here given that x is inversely depends of y

so as we increase the value of y so due to inverse dependency it will decrease the value of x

So here we can also say that when x inversely depends on y

so the product of x and y will remain constant here

so here the graph should be like this that if we increase the quantity on x axis then it will decrease the other quantity on y axis

<u><em>So here best appropriate graph must be option A</em></u>

3 0
3 years ago
A 97.1 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.63 r
sammy [17]

Answer:

the final angular velocity of the platform with its load is 1.0356 rad/s

Explanation:

Given that;

mass of circular platform m = 97.1 kg

Initial angular velocity of platform ω₀ = 1.63 rad/s

mass of banana m_{b} = 8.97 kg

at distance r = 4/5  { radius of platform }

mass of monkey m_{m} = 22.1 kg

at edge = R

R = 1.73 m

now since there is No external Torque

Angular momentum will be conserved, so;

mR²/2 × ω₀ = [ mR²/2 + m_{b} (\frac{4}{5} R)² + m_{m}R² ]w

m/2 × ω₀ = [ m/2 + m_{b} (\frac{4}{5} )² + m_{m} ]w

we substitute

w = 97.1/2 × 1.63 / ( 97.1/2 + 8.97(16/25) + 22.1

w = 48.55 × [ 1.63 / ( 48.55 + 5.7408 + 22.1 )

w = 48.55 × [ 1.63 / ( 76.3908 ) ]

w = 48.55 × 0.02133

w = 1.0356 rad/s

Therefore; the final angular velocity of the platform with its load is 1.0356 rad/s

8 0
3 years ago
When the velocity of an object Changes it is acted upon by a
anygoal [31]

When the velocity of an object changes, it is acted upon by a force

5 0
3 years ago
Which countries have high productivity, but are not among the top 10 for human development? Check all that apply.
trasher [3.6K]

Answer:

Belgium

France

Luxembourg

Explanation:

These are the ones that are in the High Productivity chart, but not in the HDI chart

8 0
3 years ago
While at a construction site, you see a crane lift a 1000kg steel beam up to a height of 10m in a time period of 5.0 seconds. A
storchak [24]

Answer:

Car has more power output than crane      

Explanation:

We have given that mass of the crane m = 1000 kg

Height through which crane lift the steel beam h = 10 m

Acceleration due to gravity g=9.8m/sec^2

So work done by crane W=mgh=1000\times 9.8\times 10=98000j

Time period is given as t = 5 sec

We know that power P=\frac{W}{t}=\frac{98000}{5}=19600watt

Now mass of the car = 1000 kg

Initial velocity u = 0 m /sec

Final velocity v = 10 m/sec

We know that work done is equal to the change in kinetic energy

So work done =\frac{1}{2}mv^2-\frac{1}{2}mu^2

=\frac{1}{2}\times 1000\times 10^2-\frac{1}{2}\times 1000\times 0^2=50000j

Time ids given as t = 2 sec

So power P=\frac{W}{t}=\frac{50000}{2}=25000watt

So car has more power output than crane

8 0
3 years ago
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