Answer:
-0.75 , 1.25
Explanation:
Number of electrons present in valence shell,
P-O = 5 + 8 = 13
Number of electrons involved in bond formation,
13 - 3 = 10
Number of bonds in PO3 - 4ion = 102
Average P-O bond = 1.25
Average formal charge on Oxygen atom is -0.75
The atomic number is equal to number of protons present in the nucleus of an atom or vice-versa. For any atom, there is no change in number of protons either by adding or removal of electron.
Since, sodium is a metal, it has tendency to lose electron in the presence of non-metal i.e. chlorine. Thus, after lose of an electron, there is no change in the number of protons or number of protons will remain same.
Therefore, atomic number of metal is 11 which is also equal to the number of protons implies sodium will have 11 protons in its nucleus.
The unit cell volume of the crystal is
and the density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3
Data;
- radius = 0.1445 nm
- c/a = 1.58
- A = 46.88 g/mol
<h3>Unit Cell Volume</h3>
The unit cell volume can be calculated as

let's substitute the values into the formula

The unit cell volume of the crystal is 
<h3>Density of Ti</h3>
The density of titanium can be calculated as

- n = 6 for hcp
- A = 46.88 g/mol
- Na = Avogadro's number
let's substitute the values into the formula

The density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3
Learn more on crystal lattice here;
brainly.com/question/6610542
Thermosphere. In this layer, atoms and molecules escape into space and satellites orbit the earth.
<span>situated or extending across something.</span>