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2 years ago

.7 liters of CO represents how many molecules?

Chemistry

1 answer:

Ronch [10]2 years ago

7 0

Answer:

1.88 × 10²² Molecules of CO

Explanation:

At STP for an ideal gas,

Volume = Mole × 22.4 L/mol

Or,

Mole = Volume / 22.4 L/mol

Mole = 0.7 L / 22.4 L/mol

Mole = 0.03125 moles

Now,

No. of Molecules = Moles × 6.022 × 10²³ Molecules/mol

No. of Molecules = 0.03125 × 6.022 × 10²³ Molecules/mol

No. of Molecules = 1.88 × 10²² Molecules of CO

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Help me plz #10 would appreciate it

DaniilM [7]

C I’m pretty sure. I can explain just lmk

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3 years ago

Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following

bearhunter [10]

Answer:

$210.7~g~MgCO_3$

Explanation:

We have to start with the reaction:

$MgCO_3~->~MgO~+~CO_2$

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the number of moles that we have in the 110.0 g of carbon dioxide, to this, we have to know the atomic mass of each atom:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the molar mass of carbon dioxide:

$(12*1)+(16*2)=44~g/mol$

In other words: $1~mol~CO_2=~44~g~CO_2$ . With this in mind, we can calculate the moles:

$110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2$

Now, the molar ratio between carbon dioxide and magnesium carbonate is 1:1, so:

$2.5~mol~CO_2=2.5~mol~MgCO_3$

With the molar mass of $MgCO_3$ ( $(23.3*1)+(12*1)+(16*3)=84.3~g/mol$ . With this in mind, we can calculate the grams of magnesium carbonate:

$2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3$

I hope it helps!

8 0

3 years ago

Recall rem = rad x q radiation weighting factor (q): the ability to transfer energy to the body 1 for photons 1 for electrons 2

tino4ka555 [31]

The biological risk for the first person than the second as a result of radiation weighting is 10 times.

<h3>What is radiation weighting factor?</h3>

As stated in the question, radiation weighting factor (q) is the ability to transfer energy to the body.

If radiation factor of proton = 2, and radiation factor of alpha particles = 20.

First person is exposed to alpha radiation = 20
Second person is exposed to protons = 2

Risk of first person with respect to second person = 20/2 = 10 times higher

Learn more about radiation factor here: brainly.com/question/24039736

#SPJ4

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2 years ago

Dr. House took two liquids of different densities (p_1=1500 kg/m^3; p_2 = 500 kg/m^3) are poured together into a 0.1 m^3 tank fi

SVETLANKA909090 [29]

We know that:
mass = density x volume
The volume of the total mixture is 0.1 m³
Let the first liquid be A and the second be B
Mass Total = Mass A + Mass B

800 x 0.1 = 1500Va + 500(0.1 - Va)
30 = 1000Va
Va = 0.03 m³
Vb = 0.1 - 0.03 = 0.07 m³

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3 years ago

The answer to (3.540)x(0.0065)x(401) should have ____.

miv72 [106K]

B. Two significant figures

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3 years ago