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3 years ago

What is physics and important of physics

2 answers:

8 0

Physics is the explanation of our reality, both visible and invisible. With it we can understand the world around us, why things are how they are, and why things do what they do. This understanding allows humans to develop objects that improve quality of life.

Arte-miy333 [17]3 years ago

4 0

Answer:

Physics is the answer to all the forces in nature and it is important to know all of that in a day to day life to succeed in life

Explanation:

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A -3.00 nc point charge is at the origin, and a second -5.50 nc point charge is on the x-axis at x = 0.800 m. find the electric

Liula [17]

The electric field produced by a single-point charge is given by

$E(r)=k\frac{q}{r^2}$

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

To find the electric field at x=0.200 m, we need to find the electric field produced by each charge at that point, and then find their resultant.

1) The first charge is $q=-3.00 nC=-3.00 \cdot 10^{-9} C$ , and it is located at x=0, so its distance from the point x=0.200 m is

$r=0.200 m-0=0.2 m$

Therefore, the electric field is

$E_1=(8.99 \cdot 10^9 Nm^2C^{-2})\frac{(3.0 \cdot 10^{-9} C)}{(0.2 m)^2}=675 N/C$

And since the charge is negative, the direction of the field is toward the charge, so toward negative x direction.

2) The second charge is $q=-5.50 nC=-5.5 \cdot 10^{-9}C$ and it is located at x=0.800 m, so its distance from the point is

$r=0.800 m-0.200 m=0.6 m$

Therefore, the electric field is

$E_2 = (8.99 \cdot 10^9 Nm^2C^{-2})\frac{(5.5 \cdot 10^{-9} C)}{(0.6 m)^2}=137.5 N$

And since the charge is negative, the direction of the field is toward the charge, so toward positive x-direction.

3) The total electric field at x=0.200 m will be given by the difference between the two fields (because they are in opposite directions). Taking the x-positive direction as positive direction, we have

$E=E_2 -E_1 =137.5 N/C/C-675 N/C=-537.5 N/C$

and the sign tells us that the field is directed toward negative x-direction.

7 0

3 years ago

Richard Julius once made a model plane that could travel a max speed of 110 m/s. Suppose the plane was held in a circular path b

hjlf

Answer:

85.8 m/s

Explanation:

We know that the length of the circular path, L the plane travels is

L = rθ where r = radius of path and θ = angle covered

Now,its speed , v = dL/dt = drθ/dt = rdθ/dt + θdr/dt

where dθ/dt = ω = angular speed = v'/r where v' = maximum speed of plane and r = radius of circular path

Now, from θ = θ₀ + ωt where θ₀ = 0 rad, ω = angular speed and t = time,

θ = θ₀ + ωt = 0 + ωt = ωt

So, v = rdθ/dt + θdr/dt

v = rω + ωtdr/dt

v = (r + tdr/dt)ω

v = (r + tdr/dt)v'/r

v = v' + tv'/r(dr/dt)

v = v'[1 + t(dr/dt)/r]

Given that v' = 110 m/s, t = 33.0s, r = 120 m and dr/dt = rate at which line is shortened = -0.80 m/s (negative since it is decreasing)

So, v = 110 m/s[1 + 33.0 s(-0.80 m/s)/120 m]

v = 110 m/s[1 + 11.0 s(-0.80 m/s)/40 m]

v = 110 m/s[1 + 11.0 s(-0.02/s)]

v = 110 m/s[1 - 0.22]

v = 110 m/s(0.78)

v = 85.8 m/s

8 0

3 years ago

When you eat a large meal and your body absorbs a lot of glucose and that makes its way to the interstitial fluid before going i

Agata [3.3K]

Answer:A. It is modified by the cell, so there is still more glucose on the outside of the cell than inside it

Explanation: The cells are the primary unit of a living organism,it is the place where cellular respiration takes place, which is the use of oxygen to break down food substances such as Glucose to release energy in the form of Adenosine trisphosphate (ATP) and give out Carbondioxide as a by-product of cellular respiration.

Most of the Glucose enter the cells to get modified through cellular respiration so their is still more Glucose outside than the Glucose inside.

6 0

3 years ago

Name two things radio waves have in common with visible light

kondaur [170]

Radio waves and visible light, as we perceive it, are both part of the EM spectrum. The only difference between them in terms of our perception is that we don't have receptors to 'see' radio waves. That's where radio receivers come into the picture*, to convert radio waves into sound impulses that we can hear.

8 0

3 years ago

In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the max

Sav [38]

Answer:

the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94

Explanation:

Given that ;

the top speed of Cheetahs is almost 60 mph

In cornering abilities ; the maximum centripetal acceleration of a cheetah was measured to be = 19 m/s^2

The objective of this question is to determine the what minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?

From the knowledge of Newton's Law;

we knew that ;

Force F = mass m × acceleration a

Also;

The net force $F_{net}$ = frictional force $\mu_k mg$