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From the calculation and the momentum of the body, the velocity is 62 m/s
<h3>What is momentum?</h3>
The term momentum refers to the product of mass and velocity. Now recall that the rate of change of momentum is equal to the impressed force.
Hence;
7440 kg-m/s = 120 kg * v
v= 7440 kg-m/s/120 kg
v = 62 m/s
Learn more about momentum:brainly.com/question/24030570
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(a) 
The relationship beween centripetal acceleration and angular speed is
where
is the angular speed
r is the radius of the circular path
Here we gave
is the centripetal acceleration
r = 5.15 m is the radius
Solving for , we find:
(b) 21.3 m/s
The relationship between the linear speed and the angular speed is
where
v is the linear speed
is the angular speed
r is the radius of the circular path
In this problem we have
r = 5.15 m
Solving the equation for v, we find
Answer:
39.4 ml
Explanation:
The displacement is the original volume plus the volume of the other object.
Explanation:
(a) Hooke's law:
F = kx
7.50 N = k (0.0300 m)
k = 250 N/m
(b) Angular frequency:
ω = √(k/m)
ω = √((250 N/m) / (0.500 kg))
ω = 22.4 rad/s
Frequency:
f = ω / (2π)
f = 3.56 cycles/s
Period:
T = 1/f
T = 0.281 s
(c) EE = ½ kx²
EE = ½ (250 N/m) (0.0500 m)²
EE = 0.313 J
(d) A = 0.0500 m
(e) vmax = Aω
vmax = (0.0500 m) (22.4 rad/s)
vmax = 1.12 m/s
amax = Aω²
amax = (0.0500 m) (22.4 rad/s)²
amax = 25.0 m/s²
(f) x = A cos(ωt)
x = (0.0500 m) cos(22.4 rad/s × 0.500 s)
x = 0.00919 m
(g) v = dx/dt = -Aω sin(ωt)
v = -(0.0500 m) (22.4 rad/s) sin(22.4 rad/s × 0.500 s)
v = -1.10 m/s
a = dv/dt = -Aω² cos(ωt)
a = -(0.0500 m) (22.4 rad/s)² cos(22.4 rad/s × 0.500 s)
a = -4.59 m/s²
