Complete Question
A small metal sphere, carrying a net charge q1=−2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2= -8μC and mass 1.50g, is projected toward q1. When the two spheres are 0.80m apart, q2 is moving toward q1 with speed 20ms−1. Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.The speed of q2 when the spheres are 0.400m apart is.
Answer:
The value
Explanation:
From the question we are told that
The charge on the first sphere is
The charge on the second sphere is
The mass of the second charge is
The distance apart is
The speed of the second sphere is
Generally the total energy possessed by when and are separated by is mathematically represented
Here KE is the kinetic energy which is mathematically represented as
substituting value
And U is the potential energy which is mathematically represented as
substituting values
So
Generally the total energy possessed by when and are separated by is mathematically represented
Here is the kinetic energy which is mathematically represented as
substituting value
And is the potential energy which is mathematically represented as
substituting values
From the law of energy conservation
So
Answer:
Total distance = 400+700+1200= 2300km
Explanation:
the resultant of d 1st right angle triangle + 1200
= 806.2 + 1200 = 2006.2km
Gravity obeys the inverse square law. At 6400 km above the center of the Earth (Earth's surface) you weigh x. Twice that reduces your weight to 1/4th. Four times that height reduces your weight to 1/16th. 4 times 6400 km is 25,600 km. But that is above the center of the earth, and the question requests the height above the surface, so we deduct 6400 km to arrive at our final answer: 19,200 km.
Incidentally, it doesn't exactly work the opposite way. At the center of the Earth the mass would be equally distributed around you, and you would therefore be weightless.
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Answer:</h3>
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Explanation:</h3>
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λ=500 nm = 500·10⁻⁹ m
c=3·10⁸ m/s
h=6,63·10⁻³⁴ J·s = 4,14·10⁻¹⁵ eV·s
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E - ?
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