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butalik [34]
3 years ago
6

The element lanthanum has two stable isotopes, lanthanum-138 with an atomic mass of 137.9 AMU and lanthanum-139 with an atomic m

ass of 138.9 AMU.
From the atomic weight of La = 138.9, one can conclude that:

A. there is an isotope of lanthanum with an atomic mass of 138.9
B. lanthanum-139 has the highest percent natural abundance
C. lanthanum-138 has the highest percent natural abundance
D. both isotopes have the same percent natural abundance
Chemistry
1 answer:
dmitriy555 [2]3 years ago
7 0

Answer:

A. there is an isotope of lanthanum with an atomic mass of 138.9

Explanation:

By knowing the different atomic masses of both Lanthanum atoms, we can not tell anything about their occurence in nature. Therefore, all the last three options are incorrect. Because, the atomic mass does not tell anything about the availability or natural abundance of an element.

Now, the isotopes of an element are those elements, which have same number of electrons and protons as the original element, but different number of neutrons. Therefore, they have same atomic number but, different atomic weight or atomic masses.

Hence, by looking at an elements having same atomic number, but different atomic masses, we can identify them as isotopes.

Thus, the correct option is:

<u>A. there is an isotope of lanthanum with an atomic mass of 138.9.</u>

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DanielleElmas [232]

Answer:

The product is significantly impure

Explanation:

In order to test for the purity of a specific sample that was synthesized, the melting point of a compound is measured. Basically speaking, the melting point identifies how pure a compound is. There are several cases that are worth noting:

  • if the measured melting point is significantly lower than theoretical, e. g., lower by 3 or more degrees, we conclude that our compound contains a substantial amount of impurities;
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Since our compound is even 10 degrees Celsius lower than expected, it indicates that the compound is significantly impure.

5 0
3 years ago
How many moles of aspartame are present in 1.00 mg of aspartame?
Diano4ka-milaya [45]

Answer:- There are 3.40*10^-^6 moles.

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mg are converted to grams and then the grams are converted to moles as:

1.00mg Aspartame(\frac{1g}{1000mg})(\frac{1mole}{294.31g})

= 3.40*10^-^6 moles of aspartame

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3 0
3 years ago
What is the oxidation number for iodine in Mg(IO3)2 ?
mestny [16]
The oxidation number of iodine is 5 in Mg(IO3)2 which can be calculated as 
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As we know that
Mg has +2
O has -2
So,
   (+2) + 2I + 6 (-2)=0
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    10 = 2I
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6 0
3 years ago
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What volume of oxygen at STP is requieres for the complete combustion of 100.50 mL of C2H2
malfutka [58]

The volume of oxygen at STP required would be 252.0 mL.

<h3>Stoichiometic problem</h3>

The equation for the complete combustion of C2H2 is as below:

2C_2H_2 + 5O_2 --- > 4CO_2 + 2H_2O

The mole ratio of C2H2 to O2 is 2:5.

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Thus, 252.0 mL of O2 gas will be required at STP.

More on stoichiometric problems can be found here: brainly.com/question/14465605

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7 0
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Which three groups of the periodic table contain the most elements classified as metalloids (semimetals)?
attashe74 [19]
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If you like my answer, please vote me a 'brainliest' - trying to improve my rank :-)

8 0
3 years ago
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