1.Golgi
2. nucleus
3.Endoplasmic
4.Mitochondria
5.Ribosome
6.Lysosome
Here we have to identify the sample which need more energy to heat the sample 1 degree Celsius.
Among the given elements magnesium will require more energy than the others to heat.
As per the definition of specific heat of a compound, the amount of heat required to increase the temperature of the material 1 degree Celsius is the specific heat of the material.
The given data are-
substance specific heat
Lead 0.129
Tin 0.21
Silver 0.235
Iron 0.449
Calcium 0.647
Granite 0.803
Aluminium 0.897
Magnesium 1.023
From the given data lead, magnesium, iron and aluminium have the specific heat 0.129, 1.023, 0.449 and 0.897 respectively. Thus magnesium will require more energy than the others to heat.
the force between the electron and the proton.
a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
the radial acceleration of the electron.
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
the speed of the electron.
c) Now use a = v² / r
where a was found above
and r was given
<span> the period of the circular motion.</span>
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given
Answer:
5x10⁻⁶ = [HTeH₄O₆⁺]
Explanation:
The first dissociation equilibrium of the telluric acid in water is:
H₂TeH₄O₆ + H₂O ⇄ HTeH₄O₆⁺ + H₃O⁺
Using H-H equation for telluric acid:
<em>pH = pKa + log₁₀ [HTeH₄O₆⁺] / [H₂TeH₄O₆]</em>
pKa of telluric acid is -logKa1
pKa = -log 2.0x10⁻⁸
pKa = 7.699
As concentration of [H₂TeH₄O₆] is 0.25M, replacing in H-H equation:
3.00 = 7.699+ log₁₀ [HTeH₄O₆⁺] / [0.25M]
-4.699 = log₁₀ [HTeH₄O₆⁺] / [0.25M]
2x10⁻⁵ = [HTeH₄O₆⁺] / [0.25M]
<h3>5x10⁻⁶ = [HTeH₄O₆⁺]</h3>
