Question

A sample of iron with a mass of 50.0 grams absorbs 2500 J of thermal energy. How much would the temperature of this sample change as a result of absorbing this amount of heat?

Answer 1

Temperature change would be 112.6° C.

Explanation:

We can find the amount or heat absorbed or emitted during any reaction by finding the product of their mass, specific heat, and change in temperature of the metal.

Mass of the iron, m = 50.0 g

Amount of heat absorbed, q = 2500 J

Change in temperature, ΔT = ?

Specific heat of Iron, C = 0.444 J/g °C

$\boldsymbol{q}=\boldsymbol{m} \times \boldsymbol{C} \times \boldsymbol{\Delta} \mathbf{T}$

Plugin the values and rearrange the equation to get the change in temperature as,

$\Delta \mathbf{T}=\frac{\mathbf{q}}{c \times m}$

$\Delta \mathrm{T}=\frac{2500 \mathrm{J}}{0.444 \frac{J}{\mathrm{g}^{\circ} \mathrm{C}} \times 50 \mathrm{g}}=112.6^{\circ} \mathrm{C}$