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Annette [7]
3 years ago
9

What type of season does Daytona Beach, FL most likely have?

Physics
2 answers:
Alexus [3.1K]3 years ago
4 0

i think its very hot summers

jolli1 [7]3 years ago
3 0

This question is very unscientific.  It uses a lot of rubber words ... "very cold", "mild", and "very hot" ... words without definite meanings, that mean different things to different people, and may even mean different things to the same person at different times.

To me, any place in North America located south of the latitude of Chicago has a climate characterized by very hot, very humid, very oppressive, mercilessly long Summers, and weak, anemic, negligible, absurd excuses for Winters.

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Eric is creating a timeline of the formation of the solar system. Which sequence best describes the formation of the solar syste
vlada-n [284]

The answer is C. nebular are star nurseries. When the massive gas being collapsing in its own weight. Local areas of gas begin to coalesce under gravity. Due to enormous pressure, nuclear fusion begins and a protostar is formed. The protostar grows into the sun as more hydrogen fuses at the core. The planetesimal materials at the edges of the protostellar discs coalesce to form planets that orbit the star.

3 0
3 years ago
Read 2 more answers
-What can you say about the snowboarder’s kinetic energy as he moves?
Damm [24]

Answer:

  His kinetic energy increases, potential energy decreases

  The sum of kinetic and potential energy is a constant at any instant before he comes to rest.

Explanation:

  Snowboarder is starting from a height and moving to the down direction. As he moves down his velocity increases, we know that kinetic energy is given by the expression \frac{1}{2} mv^2, so as he moves his kinetic energy increases.

  When the snowboarder is starting his potential energy is maximum(Potential energy = mgh), as he comes down his potential energy decreases.

  Based on this we can conclude that the sum of potential energy and kinetic energy is a constant at any instant for a snowboarder before he comes to rest.

                             mgh+\frac{1}{2} mv^2= Constant

 

7 0
3 years ago
Write the equation that links current, potential difference, and resistance
mrs_skeptik [129]

You can write the equation in 3 different ways, depending on which quantity you want to be the dependent variable.  Any one of the three forms can be derived from either of the other two with a simple algebra operation.  They're all the same relationship, described by "Ohm's Law".

==> Current = (potential difference) / (resistance)

==> Potential difference = (current) x (resistance)

==> Resistance = (potential difference) / (resistance)

4 0
3 years ago
How tall would a tower need to be if the period of a pendulum were 30. seconds
Virty [35]
We use the following expression

T = 2*pi *sqrt(l/g)

Where T is the period of the pendulum

l is the length of the pendulum

and g the acceleration of gravity

We solve for l

l = [T/2*pi]² *g = [30s/2*pi]²* 9.8 [m/s²] = 223.413 m

The tower would need to be at least 223.413 m high
4 0
3 years ago
A tennis player hits a ball 2.0 m above the ground. The ball leaves his racquet with a speed of 20 m/s at an angle 5.0 ∘ above t
goldfiish [28.3K]

Answer:

Explanation:

initial height, yo = 2 m

initial velocity, u = 20 m/s

angle of projection,θ = 5 degree

distance of net = 7 m

height of net = 1 m

Let it covers a vertical distance y in time t .

Use Second equation of motion for vertical motion

y=y_{0}+uSin\theta t-1/2 gt^{2}

y=2+20Sin5 t-4.9t^{2}

As it hits the ground in time t, so put y = 0

0=2+1.74 t-4.9t^{2}

4.9t^{2}-1.74t-2=0

t= \frac{1.74\pm\sqrt{1.74^{2}+4\times\2\times4.9}}{9.8}

Taking positive sign, t = 0.84 s

The ball travels a horizontal distance x in time t

X = 20 Cos5 x t

X =  16.76 m

As this distance is more than the distance of net, so it clears the net.

Let t' be the time taken to travel a horizontal distance equal to the distance of net

7 = 20 cos5 x t'

t' = 0.35 s

Let the vertical distance traveled by the ball in time t' is y'.

So,

y'=y_{0}+uSin\theta t'-1/2 gt'^{2}

y'=2+20Sin5 t-4.9\times0.35^{2}

y' = 2.008 m

So, it clears the net which is 1 m high.

It clears the net by a vertical distance of 2.008 - 1 = 1.008 m and horizontal distance 16.76 - 7 = 9.76 m

3 0
3 years ago
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