Answer: -
Concentration of PbI₂ = 1.5 x 10⁻³ M
PbI₂ dissociates in water as
PbI₂ ⇄ Pb²⁺ + 2 I⁻
So PbI₂ releases two times the amount of I⁻ as it's own concentration when saturated.
Thus the molar concentration of iodide ion in a saturated PbI₂ solution = [ I⁻] =
= 1.5 x 10⁻³ x 2 M
= 3 x 10⁻³ M
PbI₂ releases the same amount of Pb²⁺ as it's own concentration when saturated.
[Pb²⁺] = 1.5 x 10⁻³ M
So solubility product for PbI₂
Ksp = [Pb²⁺] x [ I⁻]²
=1.5 x 10⁻³ x (3 x 10⁻³)²
= 4.5 x 10⁻⁹
False! Primary succession is when a community has to completely start over which takes a long time.
Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte)
= freezing point constant =
m= molality = 
Let Mass of solute (KBr) = x g
Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams
Answer:
4 Fe + 6 02 ----> 2 Fe2O3
Explanation:
you need 4 iron and 6 oxygen in each side
Answer:
1. molecular
2. molecular
3. molecular
Explanation:
Molecular compounds typically exhibit covalent compound characteristics. They are pure substances formed when atoms are linked together by sharing electrons while ionic compounds are formed due to the transfer of electrons. Molecular substances tend to melt at moderately warm temperatures (i.e. 50° C) and it is overlapping as seen in compound 1, which makes it to be molecular in nature.
Molecular compounds are not affected by conductivity, hence they are electrically neutral.
Molecular compounds have a strong smell and have freezing and boiling point at accessible temperatures. A clear liquid at room temperature which has a fruity strong smell can be an organic compound. These organic compounds made up of covalent bonds and are molecular in nature.
