Answer:
23.27 L
Explanation:
The balanced reaction of ammonia and nitrogen monoxide is shown below as:
4NH₃(g) + 6NO(g) ⇒ 5N₂(g) + 6H₂O(l)
Given that:
Volume of nitrogen monoxide = 34.9 L
Since, temperature and pressure are same, volume coefficients would be same as equation coefficients.
So,
6 L of nitrogen monoxide reacts with 4 L of ammonia.
1 L of nitrogen monoxide reacts with 4/6 L of ammonia.
34.9 L of nitrogen monoxide reacts with (4/6)*34.9 L of ammonia.
Amount of ammonia required = 23.27 L
Number of moles = 0.0688 moles of NaoH
volume = 0.250 L
Molarity = moles of solute / volume ( L )
M = 0.0688 / 0.250
M = 0.28 M
Answer B
It is not good conductors of electricity or heat!
Answer:
There are way in separating mixtures of chloride salts such as that of sodium chloride and ammonium chloride. It can be done by crystallization, filtration, and sublimation. The easiest method among the three is separation by sublimation.
The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.
<h3>What is precipitate?</h3>
Precipitates are the crystal type formation, when the solute is no more dissolving in the solvent.
Imagine mixing 1 tablespoon of Epsom salt with 2 cups of ammonia, the reaction is
2NH₃ + MgSO₄ + 2H₂O → Mg(OH)₂ + (NH₄)₂SO₄
The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.
Learn more about precipitate.
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