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Ilia_Sergeevich [38]
3 years ago
14

What are the number of protons, neutrons, and electrons in an atom of Tellurium- 129?

Chemistry
1 answer:
deff fn [24]3 years ago
3 0

Answer:

Number of protons = 52, Number of electrons = 52, Number of neutrons = 76

Explanation:

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The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha
zimovet [89]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

P (Half-life) = 10.0 minutes

T (Elapsed time for sample reduction) = 25.9 minutes

Let's find the number of periods elapsed (x), let us see:

T = x*P

25.9 = x*10.0

25.9 = 10.0\:x

10.0\:x = 25.9

x = \dfrac{25.9}{10.0}

\boxed{x = 2.59}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{53.3}{2^{2.59}}

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\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark

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3 years ago
2.3 x 10²¹ particles H = __________ mol H (round to the nearest thousandth)
Natalka [10]

Taking into account the definition of avogadro's number, 3.82×10⁻³ moles of H are 2.3×10²¹ particles of H.

<h3>Avogadro's Number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>This case</h3>

Then you can apply the following rule of three: if 6.023×10²³ particles are contained in 1 mole of H, then 2.3×10²¹ particles are contained in how many moles of H?

amount of moles of H= (2.3×10²¹ particles × 1 mole)÷ 6.023×10²³ particles

<u><em>amount of moles of H= 3.82×10⁻³ moles</em></u>

Finally, 3.82×10⁻³ moles of H are 2.3×10²¹ particles of H.

Learn more about Avogadro's Number:

<u>brainly.com/question/11907018?referrer=searchResults </u>

<u>brainly.com/question/1445383?referrer=searchResults </u>

<u>brainly.com/question/1528951?referrer=searchResults</u>

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The spaceship does not have any gravitational pull. A spaceship can not produce its own gravity like Earth does.
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