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3 years ago

Which of the following compounds will experience dipole-dipole forces of attraction?

Chemistry

2 answers:

ddd [48]3 years ago

6 0

NaCl and H2S will experience dipole-dipole interaction because they are permanently polarized.

Neko [114]3 years ago

6 0

NaCl and H2s are the answers

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3 years ago

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The rate at which an electrical device converts energy from one form to another is called what

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It is called a watt and or wattage

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3 years ago

2) which statement describes ionic bonding?

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taka jest reguła

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3 years ago

CONCLUSIONS: Suppose a student titrated a sample of monoprotic acid of unknown concentration using a previously standardized sol

Zolol [24]

Concentration of unknown acid is 0.061 M

Given:

Concentration of NaOH = 0.125 M

Volume of NaOH = 24.68 mL

Volume of acid solution = 50.00 mL

To Find:

Concentration of the unknown acid

Solution: Concentration is the abundance of a constituent divided by the total volume of a mixture. The concentration of the solution tells you how much solute has been dissolved in the solvent

Here we will use the formula for concentration:

M1V1 = M2V2

0.125 x 24.68 = 50 x M2

M2 = 0.125 x 24.68 / 50

M2 = 0.061 M

Hence, the concentration of unknown acid is 0.061 M

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2 years ago

Determine how many gmol, kmol, and lbmols there are in 50 kilograms of n-hexane.

Artist 52 [7]

Answer: 581 gmol

0.581 kmol

$1.28\times 10^{-3}lbmol$

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{50\times 1000g}{86g/mol}=581mol$

1. The conversion for mol to gmol

1 mol = 1 gmol

581 mol= $\frac{1}{1}\times 581=581gmol$

2. The conversion for mol to kmol

1 mol = 0.001 kmol

581 mol= $\frac{0.001}{1}\times 581=0.581kmol$

3. The conversion for mol to lbmol

1 mol = $2.2\times 10^{-3}lbmol$

581 mol= $\frac{2.2\times 10^{-3}}{1}\times 581=1.28\times 10^{-3}lbmol$

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3 years ago