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3 years ago

Which of the following combinations led to a precipitation reaction?

Chemistry

1 answer:

Pani-rosa [81]3 years ago

3 0

(3) Silver Nitrate and Aluminium Sulfate

<u>Explanation:</u>

Silver nitrate and aluminium sulphate reacts to form Aluminium nitrate and silver sulfate.

The reaction is shown below:

6AgNO₃ (aq) + Al₂(SO₄)₃ (aq) → 2Al(NO₃)₃ (aq) + 3Ag₂SO₄ (S)

From the balanced equation we can see that Ag₂SO₄ or silver sulfate is the precipitate formed.

Aluminium sulfate and silver nitrate both are chemical compounds. There are many reactions that uses net ionic equation like acid-base neutralization reaction, redox reaction, double displacement reaction etc.

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What type of reaction occurs when you combine copper (II) chloride whit sodium hydroxide?

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In this case a double displacement reaction will take place.

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3 years ago

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3 years ago

Assuming that an acetic acid solution is 12% by mass and that the density of the solution is 1.00 g/mL, what volume of 1 M NaOH

Doss [256]

Explanation:

Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.

Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{12 g}{60 g/mol}$

= 0.2 mol

Molarity of acetic acid is calculated as follows.

Density = $\frac{mass}{volume}$

1 g/ml = $\frac{100 g}{volume}$

volume = 100 ml

Hence, molarity = $\frac{\text{no. of moles}}{volume}$

= $\frac{0.2 mol}{0.1 L}$

= 2 mol/l

As reaction equation for the given reaction is as follows.

$NaOH + CH_{3}COOH \rightarrow CH_{3}COONa + H_{2}O$

So, moles of NaOH = moles of acetic acid

Let us suppose that moles of NaOH are "x".

$x \times 1 M = 10 mL \times 2 M$ (as 1 L = 1000 ml)

x = 20 L

Thus, we can conclude that volume of NaOH required is 20 ml.

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3 years ago

Why are the oxidation and reduction half-reactions separated in an<br> electrochemical cell?

Aleksandr [31]

Answer:

<h2>It makes the current viable enough to pass through an exterior wire.</h2>

Explanation:

Electrochemical cells primarily comprise of two half-cells. These half-cells assist in isolating the oxidation and reduction half-reactions. These two reactions are linked by a wire which allows the current to move from one edge to the other. The oxidation at the anode and the reduction take place at the cathode and the addition of a salt bridge helps in completing the circuit and permits the current to flow and leads to the generation of electricity.

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2 years ago

1 pt

Degger [83]

Ghbghvdezagnlmhhbbb

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