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sleet_krkn [62]
3 years ago
9

1. _______ are atoms that carry an electric charge.

Chemistry
2 answers:
alexgriva [62]3 years ago
8 0
Protons carry a positive charge. Neutrons carry no charge. Electrons carry a negative charge
horrorfan [7]3 years ago
6 0
Atoms that carry an electric charge because they gained or lost electrons are called ions.
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Create a balanced equation of this COMBUSTION REACTION: C8H18 (hint, all combustion reactions have some things in common (CO2 an
julsineya [31]
2C8H18+72O2>>16CO2+36H2O<< balanced
8 0
3 years ago
Cells can use the glucose directly, without breaking it down, to carry out cellular processes. True or False?
Akimi4 [234]

Answer:

False

Explanation:

Glucose is a substrate which undergoes various chemical reactions in the mitochondria to produce ATP, which is the universal energy carrier.

6 0
2 years ago
How many atoms are in 490 moles of barium?
Usimov [2.4K]

Answer:

2.95 * 10^23 atoms

Explanation:

The number of atoms in a mole is always equal to <u>Avogadro's constant</u>, which is <u>6.02214076×10²³ mol⁻¹</u>.

To find the number of atoms in 0.490 moles of barium, multiply it with <u>Avogadro's constant</u>:

0.490 mol * 6.02214076×10²³ mol⁻¹ ≈ 2.9508 * 10^23

Convert to SigFigs (if necessary):

2.95 * 10^23

4 0
3 years ago
PROBLEMS
allsm [11]

Answer:

% Mass of sand = 35.95%

% Mass of KBr = 64.05%

Explanation:

From the question given, we obtained the following:

Mass of mixture( KBr + sand) = 10g

Mass of sand = 3.595g

Mass of KBr = 10 — 3.595 = 6.405g

% Mass of sand = ( Mass of sand / mass of mixture) x 100

% Mass of sand = (3.595 / 10) x100

% Mass of sand = 35.95%

We can obtain the percentage of KBr by subtracting the percentage of sand from 100. This is illustrated below:

% Mass of KBr = 100 — 35.95

% Mass of KBr = 64.05%

4 0
3 years ago
If a Geiger counter that is 1 m away from a small source reads 50 counts per minute, what will its reading be 2 m from the sourc
masya89 [10]

as the amount of radiation received is proportional to 1/d^2

2m from source


for 1m readings are 50 count per minute


for 2m =   50 / (2)^2

                   50 / 4   =  12.5 count per minute

6 0
3 years ago
Read 2 more answers
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