Answer:
Solute = 5 mL; solution = 250 mL
Explanation:
The formula for percent by volume is
![\text{Percent by volume} = \dfrac{\text{Volume of solute}}{\text{Volume of solution}}\times 100 \, \%](https://tex.z-dn.net/?f=%5Ctext%7BPercent%20by%20volume%7D%20%3D%20%5Cdfrac%7B%5Ctext%7BVolume%20of%20solute%7D%7D%7B%5Ctext%7BVolume%20of%20solution%7D%7D%5Ctimes%20100%20%5C%2C%20%5C%25)
If you have 250 mL of a solution that is 2 % v/v,
![\begin{array}{rcl}2 \, \% & = & \dfrac{\text{Volume of solute}}{\text{250 mL}}\times 100 \, \%\\\\2 \times \text{ 250 mL} & = & \text{Volume of solute} \times 100\\\text{Volume of solute} & = & \dfrac{2 \times 250\text{ mL}}{100}\\\\ & = & \textbf{5 mL}\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D2%20%5C%2C%20%5C%25%20%26%20%3D%20%26%20%5Cdfrac%7B%5Ctext%7BVolume%20of%20solute%7D%7D%7B%5Ctext%7B250%20mL%7D%7D%5Ctimes%20100%20%5C%2C%20%5C%25%5C%5C%5C%5C2%20%5Ctimes%20%5Ctext%7B%20250%20mL%7D%20%26%20%3D%20%26%20%5Ctext%7BVolume%20of%20solute%7D%20%5Ctimes%20100%5C%5C%5Ctext%7BVolume%20of%20solute%7D%20%26%20%3D%20%26%20%5Cdfrac%7B2%20%5Ctimes%20250%5Ctext%7B%20mL%7D%7D%7B100%7D%5C%5C%5C%5C%20%26%20%3D%20%26%20%5Ctextbf%7B5%20mL%7D%5C%5C%5Cend%7Barray%7D)
If there is no change of volume on mixing,
Volume of solution = 250 mL
-Volume of solute = <u> </u><u>5</u><u> </u>
Volume of solvent = 245 mL
There's 6.022×10^23 particles in 1 mole of anything
like there is 1000 grams in 1 kilogram of anything
Answer:
Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6
Bromocresol green, color change from pH = 4.0 to 5.6
Explanation:
The equation for the reaction is :
![C_2H_5NH_2_(_a_q_) + H^+_(_a_q_) --- C_2H_5NH_{3(aq)}^+](https://tex.z-dn.net/?f=C_2H_5NH_2_%28_a_q_%29%20%20%20%20%20%2B%20%20%20%20%20H%5E%2B_%28_a_q_%29%20%20%20---%20%20%20%20%20%20C_2H_5NH_%7B3%28aq%29%7D%5E%2B)
concentration of
= 10%
10 g of
in 100 ml solution
molar mass = 45.08 g/mol
number of moles = 10 / 45.08
= 0.222 mol
Molarity of ![C_2H_5NH_2(aq) = 0.222 \times \frac{1000}{100}mL](https://tex.z-dn.net/?f=C_2H_5NH_2%28aq%29%20%3D%200.222%20%5Ctimes%20%5Cfrac%7B1000%7D%7B100%7DmL)
= 2.22 M
number of moles of
in 20 mL can be determined as:
![= 20 mL \times 2.22 M= 44*10^{-3} mole](https://tex.z-dn.net/?f=%3D%2020%20mL%20%5Ctimes%20%202.22%20M%3D%2044%2A10%5E%7B-3%7D%20mole)
Concentration of ![C_2H_5NH_2(aq) = \frac{44*10^{-3}*1000}{20}](https://tex.z-dn.net/?f=C_2H_5NH_2%28aq%29%20%3D%20%5Cfrac%7B44%2A10%5E%7B-3%7D%2A1000%7D%7B20%7D)
= 2.22 M
Similarly, The pKa Value of
is given as 10.75
pKb value will be: 14 - pKa
= 14 - 10.75
= 3.25
the pH value at equivalence point is,
![pH= \frac{1}{2}pKa - \frac{1}{2}pKb-\frac{1}{2}log[C]](https://tex.z-dn.net/?f=pH%3D%20%5Cfrac%7B1%7D%7B2%7DpKa%20-%20%5Cfrac%7B1%7D%7B2%7DpKb-%5Cfrac%7B1%7D%7B2%7Dlog%5BC%5D)
![pH = \frac{14}{2}-\frac{3.25}{2}-\frac{1}{2}log [2.22]](https://tex.z-dn.net/?f=pH%20%3D%20%5Cfrac%7B14%7D%7B2%7D-%5Cfrac%7B3.25%7D%7B2%7D-%5Cfrac%7B1%7D%7B2%7Dlog%20%5B2.22%5D)
![pH = 5.21](https://tex.z-dn.net/?f=pH%20%3D%205.21)
Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6
Answer:
F - O - S - Mg - Ba
Explanation:
as you move left to right on the periodic table the number of electrons increase.