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Cloud [144]
3 years ago
7

During a water treatment program, 127 grams of calcium nitrate, Ca(NO3)2, is dissolved in water. The final volume of the solutio

n is 2,300 milliliters. What is the molarity of the solution?
Chemistry
2 answers:
Sophie [7]3 years ago
7 0

Answer is:  the molarity of the solution is 0.336 M.

m(Ca(NO₃)₂) = 127 g; mass of calcium nitrate.

n(Ca(NO₃)₂) = m(Ca(NO₃)₂) ÷ M(Ca(NO₃)₂).

n(Ca(NO₃)₂) = 127 g ÷ 164.1 g/mol.

n(Ca(NO₃)₂) = 0.77 mol; amount of calcium nitrate.

V(solution) = 2300 mL ÷ 1000 mL/L.

V(solution) = 2.3 L.

c(Ca(NO₃)₂) = n(Ca(NO₃)₂) ÷ V(solution).

c(Ca(NO₃)₂) = 0.77 mol ÷ 2.3 L.

c(Ca(NO₃)₂) = 0.336 mol/L; molarity of the solution.

ratelena [41]3 years ago
3 0

<em>Answer:</em>

  • The morality of solution is 0.33 M

<em>Data given:</em>

                                                      mass of Ca(NO3)2 = 127 g

                                    molar mass of calcium nitrate = 164.08 g/mol

                                            moles of calcium nitrate = 127/164.08 = 0.77

                                                   Volume of solution = 2300ml =2.3 L

<em>Solution</em>

  • Molarity = No. of moles × 1/vol. of solution in litre
  • M = 0.77 × 1/2.3 = 0.33 M
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I hope it helps!

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in a chemical reaction of NaOH with H2O, after NaOH is completely disassociated, we will find Na+ and OH- ions in the solution. (option C).

Explanation:

In a reaction where NaOH is added to H2O.

NaOH is considered a strong base, this means that in an aqueous solution ( in water) it's  able to completely disassociate in ions.

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