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Rasek [7]
3 years ago
14

- Marta desea preparar una bebida instantánea al 15% en g/ml y el concentrado en polvo contiene 30g. ¿Qué volumen de bebida se p

uede preparar con esta cantidad de soluto?​
Chemistry
1 answer:
madam [21]3 years ago
3 0

Answer:

No sé si lo siento

Explanation:

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PLEASE HELP, WILL MARK BRAINLIEST!!!!! TIME IS RUNNING OUT!!!!
faltersainse [42]

This is a redox reaction where oxidation and a reduction occur.

<span>Here, Mg goes to Mg²</span>⁺ <span>by changing its oxidation number from 0 to +2 while S goes to S²</span>⁻ <span>by reducing its oxidation state from 0 to -2 . Hence Mg is oxidized by S in the reaction.</span>

 

Reducing agent <span>is a substance which reduces other substance by oxidizing itself. Hence, the reducing agent of this reaction is <span>Magnesium.</span></span>

6 0
3 years ago
an acid accepts H and removes them from a solution, is a solution where the water molecules are intact
n200080 [17]
<h3>An acid accepts H and removes them from a solution</h3>

When placed in water, acids, bases, and salts dissociate (separate) into electrolytes (ions). Salts dissociate into a cation (that is not H+) and an anion (that is not OH-), whereas acids and bases dissociate into H+ and an anion. An acid separates into anions and hydrogen ions (H+). Strong acids produce a high concentration of H+ by dissociating every single one of their molecules . Water-based solutions,

Acid:

When a material or chemical is in solution, it releases hydrogen ions (H+), which are known as acids. All hydrogen ions (H+) and chloride ions (Cl-), which are normally bound together by ionic bonding, dissociate (separate) in water when exposed to a strong acid like hydrochloric acid (HCl). Only some ions disintegrate into hydrogen ions (H+) and bicarbonate ions (HCO3-) in a weak acid like carbonic acid (H2CO3), while others are still bound together by ionic bonds.

Define base?

A base is a chemical that, when in solution, emits hydroxyl ions -{OH). We can also define a base as a substance that releases hydroxyl ions (OH-), which mix with any hydrogen ions (H+) in the solution to generate water molecules (OH- + H+ = H2O).

Therefore, a substance that receives or accepts hydrogen ions (H+) that are already present in the solution qualifies as a base.

Because it totally dissociates into sodium ions (Na+) and hydroxyl ions (OH-) when placed in water, sodium hydroxide (NaOH), which is a strong base, is now liberated and dissolves in water.

c

for more information please visite:

brainly.com/question/15017356?referrer=search

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8 0
2 years ago
How many molecules are in 2.38g of SO2
Murrr4er [49]

2.63 x 10^22 molecules of SO2.

To find this, start with what you know.

2.38g of SO2.

You need to first convert this into Moles since you cannot directly convert grams into molecules. In order to convert grams to moles, you need to find the molecular mass of SO2 - 64.066.

This is because Sulfur has the mass of 32.066 and Oxygen has a mass of 16, but since there are two Oxygen atoms, it's going to be 32.

Your equation should currently appear as so:

2.38g of SO2 = 1 Mole of SO2 / 64.066

Now, you need to convert this to molecules.

Whenever you are searching for molecules without a given amount, you always use Avogadro's number: 6.02 x 10^23

Now, your equation should appear as so:

2.38g SO2 = 1 Mole of SO2 / 64.066 next to a new fraction which is 6.02 x 10^23 / 1 Mole of SO2

Now, multiply across (2.38 x 1 x 6.02 x 10^23). When using Avogadro's number, don't forget to place parenthesis around it.

Then, divide that number by the bottom: 64.066.

Thus, your final answer is that there is 2.63 x 10^22 molecules of SO2.

Don't forget your units!

Hope this helps!

5 0
3 years ago
A sample of gas occupies 3.00 L with 5.00 moles present. What would
pantera1 [17]

3/5 times 5/3x = 8*3/5. X=24/5 simplified would be x= 4.8 L.

5 0
3 years ago
2NaCl → 2Na +Cl2<br> What reaction is this
babunello [35]

Answer:

Decomposition reaction

Explanation:

A single reactant breaking down to form 2 or more products is decomposition

5 0
2 years ago
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