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Rasek [7]
3 years ago
14

- Marta desea preparar una bebida instantánea al 15% en g/ml y el concentrado en polvo contiene 30g. ¿Qué volumen de bebida se p

uede preparar con esta cantidad de soluto?​
Chemistry
1 answer:
madam [21]3 years ago
3 0

Answer:

No sé si lo siento

Explanation:

You might be interested in
ANSWER ASAP ITS CHEMISTRY HIGH SCHOOL 10 POINTS!
loris [4]

Answer:

3rd option. 1–butanamine

Explanation:

To name the compound above, the following must be observed:

1. Locate the functional group in the chain. In this case the functional group is amine.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound. In this case, the longest chain has 4 carbon i.e butane.

3. Since the functional group is amine, the parent name becomes butanamine i.e replacing the –e at the end in butane with –amine

4. Indicate the position of the functional group in the chain. In this case the functional group is at carbon 1

5. Name the compound by putting the above together.

The name of the compound is:

1–butanamine or butan–1–amine

5 0
3 years ago
Why do many people have different habits
Lady bird [3.3K]

Answer:

Explanation:

Porque la vida, nuestra vida,  está controlada de manera muy importante por nuestros hábitos, los cuales influyen, de forma, aunque inconsciente en por ejemplo: nuestra salud, productividad, seguridad económica y, como resultado, también en nuestra felicidad. En resumen, en todo y a todos  los que nos rodean.

3 0
2 years ago
Which of the following would dissolve in water?<br> CCl4<br> LiCl<br> CH4<br> PCl6
babymother [125]
Like dissolves like
so water is polar

CCl4 is nonpolar
LiCl is polar
CH4 is nonpolar
PCl6 is nonpolar

so LiCl would dissolve
7 0
2 years ago
Read 2 more answers
How many atoms of S are there?
jonny [76]
Atoms of sulfur = 9.60⋅g32.06⋅g⋅mol−1×6.022×1023⋅mol−1 . Because the units all cancel out, the answer is clearly a number, ≅2×1023 as required.
4 0
3 years ago
Read 2 more answers
How many moles of oxygen are needed to react with 87 grams of aluminum
labwork [276]

Answer:

2.4 moles of oxygen are needed to react with 87 g of aluminium.

Explanation:

Chemical equation:

4Al(s)  + 3O₂(l)   → 2AlO₃(s)

Given data:

Mass of aluminium = 87 g

Moles of oxygen needed = ?

Solution:

Moles of aluminium:

Number of moles of aluminium= Mass/ molar mass

Number of moles of aluminium= 87 g/ 27 g/mol

Number of moles of aluminium= 3.2 mol

Now we will compare the moles of aluminium with oxygen.

                              Al         :         O₂

                               4          :         3

                               3.2       :         3/4×3.2 = 2.4 mol

2.4 moles of oxygen are needed to react with 87 g of aluminium.

5 0
2 years ago
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