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Anon25 [30]
4 years ago
7

The electron affinities of the elements from aluminum to chlorine are -44, -120, -74, -200.4, and -384.7 kJ/mol, respectively. R

ationalize the trend in these values.
Chemistry
1 answer:
Sidana [21]4 years ago
3 0

Answer:

Electron affinity increases when moving left to right of the period.

Explanation:

Electron affinity is the amount of energy released when an isolated gaseous atom accepts electron to form the corresponding anion.

Trend of electron affinity across the period:-

  • Across the period, the electron affinity increases as there is an increase in effective nuclear charge.  
  • Due to this, there is more force of attraction between the nucleus and the valence electrons when moving left to right in a period.  
  • Thus, more amount of energy is released when an electron is being gained in the neutral atom to form anion.  
  • Thus, electron affinity increases when moving left to right of the period.

Thus,  

Al : -44 kJ/mol

Si : -120 kJ/mol

P :  -74 kJ/mol

S :  -200.4 kJ/mol

Cl :  -384.7 kJ/mol

Al, Si, P, S, Cl are the members of third period and thus, left to right, the electron affinities of the elements increases as can be seen from the literature values.

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Answer:

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Explanation:

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4 0
3 years ago
It took 70 seconds for 280cm³ of nitrogen to diffuse through a membrane. If Carbon(IV)Oxide is allowed to diffuse through the sa
Romashka-Z-Leto [24]

Answer:

t = 125.3 seconds

Explanation:

Molar mass of CO2 = 12+2(16) = 66

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rate of diffusion of N2 = volume/ time = 280cm³/70s

= 4cm³/s

let rate of CO2 = rate of diffusion of CO2 = volume/time

= 400/t

Using Graham's law of diffusion,

rN2/rCO2 = √M(CO2)/M(N2)

4/400/t =√44/28 = 4t/400= √11/7

t/100 = 1.253 , t= (100)(1.253)

t = 125.3 seconds

hence it takes CO2 125.3 seconds to diffuse through the membrane

5 0
3 years ago
Calculate the acceleration of a car if its speed increases from 4.0 m/s to 16 m/s in 3.7 s.
ioda

Answer:

3.24m/s^2

Explanation:

The following data were obtained from the question:

U = 4m/s

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t = 3.7secs

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a = (V — U) / t

a = (16 — 4) / 3.7

a = 12/3.7

a = 3.24m/s^2

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