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solong [7]
3 years ago
14

Any body moving with simple harmonic motion is being acted on by a force that is:__________.

Physics
1 answer:
Stella [2.4K]3 years ago
6 0

Answer:

B

Explanation:

Because this oscillations occur when the restoring force is directly proportional to displacement, given as

F=-kx

Where k= force constant

X= displacement

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A certain copper wire has a resistance of 13.0 Ω . At some point along its length the wire was cut so that the resistance of one
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Answer with Explanation:

Let r be the resistance of short piece of copper wire.

Resistance of copper wire=R=13\Omega

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If a wire has greater resistance then,the wire will be greater in length.

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Total resistance of copper  wire=Sum of resistance of two piece of wires

r+7r=13

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r=\frac{13}{8}ohm

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Resistance of short piece of wire =\frac{13}{8}\Omega

Resistivity of wire and cross section area of wire remains same .

Let L be the total  length  of wire and L' be the length of short  piece of wire.

We know that

R=\frac{\rho L}{A}=\frac{\rho}{A}L=KL

\frac{R}{L}=K

Where K=\frac{\rho}{A}=Constant

Using the formula

\frac{13}{L}=\frac{\frac{13}{8}}{L'}

\frac{L'}{L}=\frac{13}{8}\times \frac{1}{13}=\frac{1}{8}

L'=\frac{L}{8}

Length of short piece of wire=L'=\frac{L}{8}

Length of long piece of  wire=L-L'=L-\frac{L}{8}=\frac{8L-L}{8}=\frac{7}{8}L

% of length of short piece of   wire=\frac{\frac{L}{8}}{L}\times 100=12.5%%

The resistance of the short piece=\frac{13}{8}\Omega

The resistance of the long piece=\frac{91}{8}\Omega

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This is due to solids having little movement/vibrations allowing for the particles to be compact. They don't get to have much freedom.

Most to least will
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