Answer:
The light bends away from the normal
Explanation:
We can solve the problem by using Snell's law:

where:
is the index of refraction of the first medium
is the index of refraction of the second medium
is the angle of incidence (angle between the incoming ray and the normal to the interface)
is the angle of refraction (angle between the outcoming ray and the normal to the interface)
We can rearrange the equation as

In this problem, light travels from an optically denser medium to an optically rarer medium, so

Therefore, the term
is greater than 1, so

which means that the angle of refraction is greater than the angle of incidence, and so the light will bend away from the normal.