<span><span>Free fall distance h=<span /></span></span>78.4532 m<span><span><span>
</span></span><span>Free fall velocity v=</span></span>39.2266 m/s<span><span><span>
</span></span><span>= </span></span>141.21576 km/h<span><span><span>
</span></span></span>
Answer:
Ummmm
Explanation:
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Answer:
1/3
Explanation:
We can solve the problem by using the lens equation:

where
f is the focal length
p is the distance of the object from the lens
q is the distance of the image from the lens
Here we have a divering lens, so the focal length must be taken as negative (-f). Moreover, we know that the object is placed at a distance of twice the focal length, so

So we can find q from the equation:

Now we can find the magnification of the image, given by:

Answer:
Explanation:
according to einstein's formulae E=mc2 1kg of mass is equivalent to (9joules when rounded off )
in this situation we ignore the bridge height and work hand in hand with the relativity and force
so...if you do the conversion you will find the suitable answer which is 16.9J