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Jlenok [28]
3 years ago
14

A simple pendulum is known to have a period, T = 1.55 s. Student A uses their smartphone stopwatch app to measure the total time

for 5 oscillations and divides that by 5 to report an average period of T = 1.25 s. Student B uses the same technique but goes old school and whips out his grandpa’s analog stopwatch to come up with an average of T = 1.5 s. What is the most probable source of error that explains the different results?
Physics
1 answer:
arsen [322]3 years ago
5 0

Given that,

Time period of simple pendulum is 1.55 s.

Time period of simple pendulum for A student =1.25 s

Time period of simple pendulum for B student =1.5 s

We know that

The accuracy is defined as how close a measurement is to a known value .

The result of student of A is 1.25 s. It is more precise because it has more significant figure than student B's result of 1.6 s.

But the measurement made by student B's is much closer the known value of 1.55 s.

Hence, The most probable source of error is the result of student A.

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A centrifugal pump discharges 300 gpm against a head of 55 ft when the speed is 1500 rpm. The diameter of the impeller is 15.5 i
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Question 2: speed of similar pump is 2067rpm

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Question 1:

Flow rate of pump 1 (Q1) = 300gpm

Flow rate of pump 2 (Q2) = 400gpm

Head of pump (H)= 55ft

Speed of pump1 (v1)= 1500rpm

Speed of pump2(v2) = ?

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Diameter of impeller in pump 2= 15in = 0.381

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Assuming cold water, S.G = 1.0

eff= (H x Q x S.G)/ 3960 x B.H.P

= (55x 300x 1)/3960x 6

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Question 2:

Q = A x V. (1)

A1 x v1 = A2 x V2. (2)

Since A1 = A2 = A ( since they are geometrically similar

A = Q1/V1 = Q2/V2. (3)

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