Answer:
Ffriction = 90 N
coefficient = 0.3
Explanation:
First, note that the sum of all the forces in the x directions equals the mass multiplied by the acceleration in the x direction.
assuming the direction of the pulling force is positive,
243 N - Ffriction = m * a
m= 30.6 kg
a= 5 m/s/s
Ffriction= 243 - m*a
Ffriction= 243 - (30.6)(5)
Ffriction=90 N
The force of friction is equal to the coefficient of friction multiplied by the normal force on the object. Because the pulling force is completely horizontal, the normal force of the object is equal to its weight, which is m * g, or (30.6 kg)(9.8 m/s/s) = 299.88 N
Ffriction = coefficient * Fnormal
90 = coefficient * 299.88
coefficient = 0.3
Answer:
120°
Explanation:
Given forces with magnitude F and F
Applying the parallelogram law of vector
Where resultant is given as :
R = √(A^2 + B^2 + 2ABCos Ф
WHERE A and B are two forces with angle Ф
F =√(F^2 + F^2 + 2F * F Cos Ф
Square both sides
F^2 = F^2 + F^2 + 2F^2 CosФ
F^2 - 2F^2 = 2F^2 CosФ
- F^2 = 2F^2 Cos Ф
Divide both sides by 2F^2
- 1 / 2 = CosФ
Cosine(theta) = - 1/2
Ф = cosi^-1 (-1/2)
Ф = 120°
Answer:
The main objective is to run out of cards.
Explanation:
The game starts by dealing 7 cards to everyone. When someone puts a card the next player has to put a card with the same number or the same color as the last card on the field. There are cards with effects such as: make the next player skip his turn, change the order of putting cards on the field or, make the next player draw 2 cards and skip his turn. If you are don't have the right color or the right number in your hand you can either put one of the black cards (if you have one of them in your hand) which let you change the color on the field (and one of them makes the next player draw 4 cards) or draw one card and skip your turn. When you have 1 card left you have to say "Uno" and when you are out of cards you win.
To solve this problem we will apply the two concepts mentioned. To find the constant we will apply Hooke's law, and to find the period we will apply the relationship between the mass and the spring constant. Let us begin,
PART A) For this section we will use Hooke's law. In turn, since the force applied is equivalent to weight, we will use Newton's law for which weight is defined as the product between mass and gravity. This weight is equal to the Spring Force.
Here,
k = Spring constant
= Displacement
F = Force, the same as the Weight (mg)
Then we have that
Therefore the spring constant is 13.23N/m
PART B) To find the period of oscillation, the relationship that allows us to find is given by the following mathematical function,
Here
m = mass
k = Spring constant
Replacing,
Therefore the period of the oscillation is 0.491s
