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Brrunno [24]
3 years ago
13

when an object moves down and does not stop which force is acting more strongly on the object, friction or gravity? explain

Physics
1 answer:
lina2011 [118]3 years ago
7 0

Gravity acts more strongly on the object.

<u>Explanation:</u>

When an object is dropped from a height, it reaches the ground despite friction acting on it because the force of gravity acting on it is stronger than the air resistance and friction. Air resistance and friction acts upward and prevents the ball from falling. However, it is negligible. The gravity acting on the object is so strong that it pulls the object towards earth with a constant acceleration called as acceleration due to gravity which has a constant value of 9.8m/s².

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AnnZ [28]

Answer:

204 m

Explanation:

When the marble is dropped from a certain height, its gravitational potential energy converts into kinetic energy. So the kinetic energy gained is equal to the variation of gravitational potential energy:

\Delta U=mg\Delta h

where

m is the mass of the marble

g = 9.8 m/s^2 is the acceleration of gravity

\Delta h is the change in height

In this problem, we have

m = 50 g = 0.05 kg

\Delta U = 100 J

Solving the formula for \Delta h, we find the necessary height from which the marble should be dropped:

\Delta h = \frac{\Delta U}{mg}=\frac{100}{(0.05)(9.8)}=204 m

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3 years ago
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Arte-miy333 [17]
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A rope of total mass m hnd length L is suspended vertically with an object of mass M suspended from the lower end. Find an expre
pantera1 [17]

Answer:

Part a)

v = \sqrt{xg + \frac{MLg}{m}}

Part b)

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Explanation:

Part a)

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T = \frac{m}{L}xg + Mg

so the speed of the wave at that position is given as

v = \sqrt{\frac{T}{\mu}}

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now we have

v = \sqrt{\frac{ \frac{m}{L}xg + Mg}{m/L}

v = \sqrt{xg + \frac{MLg}{m}}

Part b)

time taken by the wave to reach the top is given as

t = \int \frac{dx}{\sqrt{xg + \frac{MLg}{m}}}

t = \frac{1}{g}(2\sqrt{xg + \frac{MLg}{m}})

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3 years ago
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Rus_ich [418]

Answer:

Both are attractive as well as repulsive.

Explanation:

(Like poles repel, like charges<em> repel</em>; unlike poles attract, unlike charges <em>attract</em>).

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Blizzard [7]

Answer: D

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So, both technician A and B are incorrect

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