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Damm [24]
3 years ago
10

Before the experiment, the total momentum of the system is 2.5 kg m/s to the right and the kinetic energy is 5J. After the exper

iment, the total momentum of the system is 2.5 kg m/s to the right and the kinetic energy is 4J.
a. This describes an elastic collision (and it could NOT be inelastic).
b. This describes an inelastic collision (and it could NOT be elastic).
c. This is NEITHER an elastic collision nor an inelastic collision.
d. This describes a collision that is EITHER elastic or inelastic, but more information is required to determine which.
Physics
1 answer:
finlep [7]3 years ago
5 0

Answer:

Option (b) is correct.

Explanation:

Elastic collision is defined as a collision where the kinetic energy of the system remains same. Both linear momentum and kinetic energy are conserved in case of an elastic collision.

Inelastic collision is defined as a collision where kinetic energy of the system is not conserved whereas the linear momentum is conserved. This loss of kinetic energy may due to the conversion to thermal energy or sound energy or may be due to the deformation of the materials colliding with each other.

As given in the problem, before the collision, total momentum of the system is 2.5~Kg~m~s^{-1} and the kinetic energy is 5~J. After the collision, the total momentum of the system is  2.5~Kg~m~s^{-1}, but the kinetic energy is reduced to 4~J. So some amount of kinetic energy is lost during the collision.

Therefor the situation describes an inelastic collision (and it could NOT be elastic).

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What two variables are multiplied together to calculate mass?
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or

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8 0
4 years ago
Which term best describes the form of beryllium shown
astra-53 [7]

Answer:

✓ Ion

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3 0
3 years ago
A small mirror is attached to a vertical wall, and it hangs a distance of 1.87 m above the floor. The mirror is facing due east,
Oksana_A [137]

Answer:

 t = 1.62 h

Explanation:

A flat mirror fulfills the law of reflection where the incident angle is equal to the reflected angle.

          θ_i = θ_r

If we use trigonometry to find the angles, the mirror is at a height of L = 1.87 m,   and the reflected rays reach a distance x1 = 3.56 m

         tan θ₁ = x₁ / L

         tan θ₁ = \frac{3.56}{1.87}

         θ₁ = tan⁻¹  1.90

         θ₁ = 62.29º

for the second case x₂ = 1.46 m

        tan θ₂ = x₂ / L

        θ₂ = tan⁻¹  \frac{1.46}{1.87}

        θ₂ = 37.98º

the difference in degree traveled is

         Δθ = θ₁- θ₂

          Δθ = 62.29 - 37.98

          Δθ = 24.31º

as in the exercise they indicate that every 15º there is an hour

         t = 24.31º (1h / 15º)

         t = 1.62 h

4 0
3 years ago
When the current through a circular loop is 5.7 A, the magnetic field at its center is 3.9 ✕ 10−4 T. What is the radius (in m) o
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Radius of the circular loop is 0.0091m.

<h3>What is magnetic field?</h3>

Magnetic field is the area around a magnet where the magnetism influence is felt .

<h3>What is the magnetic field at the centre of a circular loop?</h3>
  • The formula for magnetic field at the centre of a loop is

B =(μ)I/2r

  • where B= Magnetic field at the centre of a circular loop

μ= Magnetic permeability =4(π)*10^(-7)

I= current flowing through the loop

r= radius of the loop

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=0.0091m

Thus, we can conclude that the radius of the loop is 0.0091m .

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8 0
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