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Damm [24]
3 years ago
10

Before the experiment, the total momentum of the system is 2.5 kg m/s to the right and the kinetic energy is 5J. After the exper

iment, the total momentum of the system is 2.5 kg m/s to the right and the kinetic energy is 4J.
a. This describes an elastic collision (and it could NOT be inelastic).
b. This describes an inelastic collision (and it could NOT be elastic).
c. This is NEITHER an elastic collision nor an inelastic collision.
d. This describes a collision that is EITHER elastic or inelastic, but more information is required to determine which.
Physics
1 answer:
finlep [7]3 years ago
5 0

Answer:

Option (b) is correct.

Explanation:

Elastic collision is defined as a collision where the kinetic energy of the system remains same. Both linear momentum and kinetic energy are conserved in case of an elastic collision.

Inelastic collision is defined as a collision where kinetic energy of the system is not conserved whereas the linear momentum is conserved. This loss of kinetic energy may due to the conversion to thermal energy or sound energy or may be due to the deformation of the materials colliding with each other.

As given in the problem, before the collision, total momentum of the system is 2.5~Kg~m~s^{-1} and the kinetic energy is 5~J. After the collision, the total momentum of the system is  2.5~Kg~m~s^{-1}, but the kinetic energy is reduced to 4~J. So some amount of kinetic energy is lost during the collision.

Therefor the situation describes an inelastic collision (and it could NOT be elastic).

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Read 2 more answers
A bicyclist starts at rest and speeds up to 30 m/s while accelerating at 4 m/s^2. Determine the distance traveled.
raketka [301]

Answer:

Distance, d = 112.5 meters

Explanation:

Initially, the bicyclist is at rest, u = 0

Final speed of the bicyclist, v = 30 m/s

Acceleration of the bicycle, a=4\ m/s^2

Let s is the distance travelled by the bicyclist. The third equation of motion is given as :

v^2-u^2=2as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{(30)^2}{2\times 4}

s = 112.5 meters

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6 0
3 years ago
What is the speed of the animal from 0-20s? <br><br> 50 m/s<br> 0.4 m/s<br> 20 m/s<br> 2.5 m/s
Shkiper50 [21]

Answer:

2.5 m/s

Explanation:

The speed of the animal is given by the ratio between the distance travelled by the animal and the time elapsed:

v=\frac{d}{t}

where d is the distance travelled and t the time elapsed. Note that this quantity is also equal to the slope of the curve.

In the time interval 0-20 s, we have

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t = 20 s - 0 s = 20 s

So, the speed is

v=\frac{50 m}{20 s}=2.5 m/s

3 0
3 years ago
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