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lesya692 [45]
3 years ago
5

Look at the picture i even had a hard time getting the pictures on here please help

Physics
1 answer:
Luden [163]3 years ago
6 0
Here's my guesses.
1 sea stack ... A2 inlet ... E3 sand spit ... F4 sea arch ... B (looks like a land arch made by the sea ... ?)5 lagoon ... C6 barrier island ...A7 bay ... D8 sea cliff .... J9 sea cave .... G10 tombolo .... no idea
That's a lot of work for 9 points !!!!
You might be interested in
Gravitational energy can be negative?
AlladinOne [14]

answer:

yes

explanation:

At a separation of the surface of Earth (r=6400km) gravity wants pull the test mass closer and closer. ... So the work done by gravity is NEGATIVE. The gravitational potential energy is negative because us trying to do the opposite of what gravity wants needs positive energy.

6 0
3 years ago
The objects listed are placed at the top of a ramp and roll down to the bottom without slipping. Assuming that there is no air r
Thepotemich [5.8K]

Explanation:

For each object, the initial potential energy is converted to rotational energy and translational energy:

PE = RE + KE

mgh = ½ Iω² + ½ mv²

For the marble (a solid sphere), I = ⅖ mr².

For the basketball (a hollow sphere), I = ⅔ mr².

For the manhole cover (a solid cylinder), I = ½ mr².

For the wedding ring (a hollow cylinder), I = mr².

If we say k is the coefficient in each case:

mgh = ½ (kmr²) ω² + ½ mv²

For rolling without slipping, ωr = v:

mgh = ½ kmv² + ½ mv²

gh = ½ kv² + ½ v²

2gh = (k + 1) v²

v² = 2gh / (k + 1)

The smaller the value of k, the higher the velocity.  Therefore:

marble > manhole cover > basketball > wedding ring

7 0
3 years ago
A typical student listening attentively to a physics lecture has a heat output of 100 w . how much heat energy does a class of 1
nexus9112 [7]

Since each student emits 100 W, so 170 students will emit:

total heat = 100 W * 170 = 17,000 W

 

Convert minutes to seconds:

time = 50 min * (60 s / min) = 3000 s

 

The energy is therefore:

E = 17,000 W * 3000 s

<span>E = 51 x 10^6 J = 51 MJ</span>

7 0
3 years ago
A small metal ball is given a negative charge, then brought near to end a of the rod (figure 1). What happens to end a of the ro
erma4kov [3.2K]

What happens to end a of the rod when the ball approaches it closely this first time is; It is strongly attracted.

<h3>Electrostatics</h3>

I have attached the image of the rod.

We are told that the ball is much closer to the end of the rod than the length of the rod. Thus, if we point down the rod several times, the distance of approach will experience no electric field and as such the charge on end point A of the rod must be comparable in magnitude to the charge on the ball.

This means that their fields will cancel.

Finally, we can conclude that when a charge is brought close to a conductor, the opposite charges will all navigate to the point that is closest to the charge and as a result, a strong attraction will be created.

This also applies to a strong conducting rod and therefore it is strongly attracted.

Read more about Electrostatics at; brainly.com/question/18108470

7 0
2 years ago
Galileo attempted to measure the speed of light by measuring the time elapsed between his opening a lantern and his seeing the l
Dafna11 [192]

Answer:

The distance is 2.58\times10^{7}\ m.

Explanation:

Given that,

Time \Delta t = 0.2\ s

The velocity is no more than a 14 % error in the speed of light.

So,

Velocity v= c\times 86\%

We need to calculate the distance

Using formula of speed

v = \dfrac{d}{t}

d = v\times t

Where, v = speed

d = distance

t = time

Put the value into the formula

d = 3\times10^{8}\times\dfrac{86}{100}\times0.2

d=516\times10^{5}\ m

We know that,

The one side distance d' is

d'=\dfrac{d}{2}

d'=\dfrac{516\times10^{5}}{2}

d'=2.58\times10^{7}\ m

Hence, The distance is 2.58\times10^{7}\ m.

5 0
3 years ago
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