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Gnom [1K]
3 years ago
11

PLEASE HELP ME!!

Mathematics
1 answer:
Ludmilka [50]3 years ago
6 0

Answer:

<h2>The population will reach 1200 after about 2.8 years</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

The population of a certain species of bird in a region after t years can be modeled by the function P(t) = 1620/ 1+1.15e-0.42t , where t ≥ 0. When will the population reach 1,200?

According to question we are to calculate the time t that the population P(t) will reach 1200.To do this we will substitute P(t) = 1,200 into the equation and calculate for the time 't'.

Given;

P(t) = \frac{1620}{1+1.15e^{-0.42t} } \\\\at \ P(t)= 1200;\\\\1200 =  \frac{1620}{1+1.15e^{-0.42t} }\\\\cross\ multiplying\\\\1+1.15e^{-0.42t} = \frac{1620}{1200} \\\\1+1.15e^{-0.42t}  = 1.35\\\\1.15e^{-0.42t} = 1.35-1\\\\e^{-0.42t} = \frac{0.35}{1.15}\\ \\e^{-0.42t}  = 0.3043\\\\Taking \ ln\ of\ both\ sides\\\\lne^{-0.42t}  = ln0.3043\\\\-0.42t = -1.1897\\\\t = \frac{-1.1897}{-0.42} \\\\t = 2.8 years\\\\

The population will reach 1200 after about 2.8 years

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Answer:

The answer is B) 72

Step-by-step explanation:

find the bigger arc: 360 - 108 = 252

x = 252 - 108/2

x = 144/2

x = 72

3 0
3 years ago
Read 2 more answers
Tina is saving to buy a notebook computer. She has two options. The first option is to put $500 away initially and save $10 ever
Alexxandr [17]

Answer:

Tina would save the same amount using either option after 20 months.

With either option, Tina would save $700.

Step-by-step explanation:

This problem can be modeled by a first order equation:

Where Tina's saved money after n months is:

S(n) = S(0) + rn, where S(0) is the money put away initially and r is how much she saves every month.

The first option is to put $500 away initially and save $10 every month, so:

S_{1}(n) = 500 + 10n

The second option is to put $100 away initially and save $30 every month, so:

S_{2}(n) = 100 + 30n

After how many months would Tina save the same amount using either option?

It will happen at the month n in which S_{1}(n) = S_{2}(n), so:

S_{1}(n) = S_{2}(n)

500 + 10n = 100 + 30n

500 - 100 = 30 - 10n

400 = 20n

20n = 400

n = \frac{400}{20}

n = 20.

Tina would save the same amount using either option after 20 months.

How much would she save with either option?

We can choose S_{1}(20) or S_{2}(20), since they are equal

S_{1}(20) = 500 + 10(20) = 500 + 200 = 700

With either option, Tina would save $700.

3 0
3 years ago
I really need this answer to be correct
Fed [463]
It is unchanged because the same number would still be in the middle and there would still be the same amount of numbers

if
11,15,21,22,23,27,30 before 22 is the median

if
11,15,21,22,23,27,30 after 22 is still the median

The median is unchanged
4 0
4 years ago
1. Elissa is buying a new car. She has an excellent credit score of
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Answer:

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Step-by-step explanation:

<u>Monthly Payment Formula</u>

\sf PMT=\dfrac{Pi(1+i)^n}{(1+i)^n-1}

where:

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  • P = loan amount
  • i = interest rate per month (in decimal form)
  • n = term of the loan (in months)

Given:

  • P = $19,500 - $4,000 = $15,500
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\implies \sf PMT=\dfrac{15500 (\frac{0.0225}{12})(1+\frac{0.0225}{12})^{60}}{(1+\frac{0.0225}{12})^{60}-1}

\implies \sf PMT=273.3788438

\implies \sf PMT=\$273.38

7 0
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Answer:

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Step-by-step explanation:

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