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FinnZ [79.3K]
3 years ago
12

A box of snacks-size cracker packs weighs 28 1/2 ounces. Each snack pack weighs 4 3/4 ounces. How many snack packs are in the bo

x?
Mathematics
2 answers:
NISA [10]3 years ago
6 0
Six because 28.5 divided by 4.75 is six
alina1380 [7]3 years ago
6 0

Answer:

<em><u>The answer is</u></em>:<u> 6 which are the packages in the box.</u>

<u />

Step-by-step explanation:

If the box weighs 28.5 ounces and each package weighs 4.75 ounces, dividing it comes out: 6 which are the packages in the box.

<em><u>The answer is</u></em>:<u> 6 which are the packages in the box.</u>

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Quadrilateral A^ prime B^ prime C^ prime D^ prime is the image of quadrilateral ABCD under a rotation about point Q
Yuliya22 [10]

Answer:

D: 90

Step-by-step explanation:

3 0
2 years ago
Find the missing term.
igor_vitrenko [27]

Equations are used to relate equal expressions.

The missing term is: \mathbf{  m -1}

The equation is given as:

\mathbf{\frac{m - n}{m^2 - n^2} + \frac{?}{(m -1)(m -n)} = \frac{2m}{m^2 - n^2}}

Express \mathbf{m^2 - n^2\ as\ (m - n)(m + n)}

So, we have:

\mathbf{\frac{m - n}{(m - n)(m + n)} + \frac{?}{(m -1)(m -n)} = \frac{2m}{(m - n)(m + n)}}

Multiply through by \mathbf{m - n}

\mathbf{\frac{m - n}{m + n} + \frac{?}{m -1} = \frac{2m}{m + n}}

Collect like terms

\mathbf{ \frac{?}{m -1} = \frac{2m}{m + n} - \frac{m - n}{m + n}}

Take LCM

\mathbf{ \frac{?}{m -1} = \frac{2m - m + n}{m + n} }

\mathbf{ \frac{?}{m -1} = \frac{m + n}{m + n} }

Divide \mathbf{ \frac{m + n}{m + n} }

\mathbf{ \frac{?}{m -1} = 1}

Cross multiply

\mathbf{ ? =(m -1)\times 1}

\mathbf{ ? =m -1}

Hence, the missing term is: \mathbf{  m -1}

Read more about equations at:

brainly.com/question/15668451

5 0
2 years ago
Suppose that 10% of all homeowners in an earthquake-prone area of California are insured against earthquake damage. Four homeown
guapka [62]

Remainder of question:

Find the probability distribution of x

Answer:

The random variable x is defined as: X = {0, 1, 2, 3, 4}

The probability distribution of X:

P(X = 0) = 0.656

P(X = 1) = 0.2916

P(X= 2) = 0.0486

P(X=3) = 0.0036

P(X = 4) = 0.0001

Step-by-step explanation:

Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

10% (0.1) of the homeowners are insured against earthquake, p = 0.1

Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

q = 0.9

Probability distribution of x,

P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) =  (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001

5 0
3 years ago
Distance: Jack and Jill start from the same point and walk in'opposite directions. Jack
777dan777 [17]

Answer:

t = 6 km/hour

And, J would be 4 km per hour

Step-by-step explanation:

Let us assume the speed of Tom be T

And, the Speed of Jim  be J

Given that  

T - J = 2 km /hr ...........(i)

After 3 hours distance between them  = 30 km

As they are walking in the opposite direction

Thus,  

Net speed =T + J

L ÷ (T+J) = 3

30 ÷ (T+J) = 3

T +J =10 ..............(2)

After solving these two equations

2T = 12

t = 6 km/hour

And, J would be 4 km per hour

6 0
2 years ago
Please answer these two questions precisely :)
GuDViN [60]
1. A)
7x= 3(35)
7x= 105
105/7= 15
Therefore x=15

2. C)

4 0
3 years ago
Read 2 more answers
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