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Dennis_Churaev [7]
3 years ago
7

Math Math Math Math Math

Mathematics
2 answers:
AlekseyPX3 years ago
7 0

Answer:

sqrt(2)+ sqrt(98)

sqrt(2) + sqrt( 2*49)

sqrt(2) + 7sqrt(2)

8 sqrt(2)

Step-by-step explanation:

Have a good day

nikdorinn [45]3 years ago
3 0

Answer:

see below

Step-by-step explanation:

sqrt(2)+ sqrt(98)

sqrt(2) + sqrt( 2*49)

sqrt(2) + 7sqrt(2)

8 sqrt(2)

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In a particular game, a fair die is tossed. If the number of spots showing is either four or five, you win $1. If the number of
TiliK225 [7]

Answer:

The probability that you win at least $1 both times is 0.25 = 25%.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either you win at least $1, or you do not. Games are independent. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of winning at least $1 on a single game:

The die has 6 sides.

If it lands on 4, 5 or 6(either of the three sides), you win at least $1. So

p = \frac{1}{2} = 0.5

You are going to play the game twice.

This means that n = 2

The probability that you win at least $1 both times is

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.5)^{2}.(0.5)^{2} = 0.25

The probability that you win at least $1 both times is 0.25 = 25%.

4 0
3 years ago
A.104<br> B.95<br> C.85<br> D.114
GarryVolchara [31]

D 114 is the answer

7 0
3 years ago
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Evaluate the following expression.<br><br> (-3)-2
natta225 [31]
-5 is your answer :))))


4 0
3 years ago
Simplify 120+x , if x&lt;−120
avanturin [10]

Answer:

Step-by-step explanation:not sure I’m sorry

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3 years ago
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How would you set up this problem to find the height of the sail using reciprocal functions?
AVprozaik [17]

Remark

I'm not sure I know what you mean, but I will answer trying to interpret it so it fits the description of the question.

Step One: Set up the equation. The normal way of solving this would be to use the Cos function.

Cos(theta) = Adjacent / hypotenuse = x/8 Multiply both sides by 8

8*cos(theta) = x Theta = 35

8*cos(35) = x This is about as simple a way as is possible.

6.553 = the height of the sale.

Step Three: try using the reciprocal

1 / cos(35)= hypotenuse / adjacent

1/0.8191 = 8/x cross multiply

x = 0.8191 * 8

x = 6.553

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