The table compares the number of electrons in two unknown neutral atoms.
2 answers:
<u>Answer:</u>
<em>Option B is the Answer. </em>
<em>Both are highly reactive.</em>
<em></em>
<u>Explanation:</u>
For a neutral atom,
Atomic number = number of electrons = number of protons.
We can identify the element from its atomic number
It says 9 and 11 are the atomic number. By looking at the periodic table we know the elements are Fluorine and sodium.
Na has 2 electron in the first shell and 8 in the second and 1 in the outer shell
F has 2 electron in the first shell and 7 in the outer shell.
Atoms with less than 8 electrons in the outer shell are not stable. In order to attain stability atom either loses or gains or shares its electron and gets 8 electron in its outer shell to become more reactive.
Sodium easily loses its outer shell electron and becomes reactive
Na (2,8,1) becomes (2, 8)
Fluorine gains easily an electron and becomes reactive.
F (2, 7) becomes (2, 8)
Having 8 electrons in its outershell electron makes an atom more stable.
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The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa
To solve that we need to apply Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:
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The oxidation is occurring on Calcium ions as it release one electron and reduction will be occurring on fluorine ion as it accepts one electron.
<u>Explanation:</u>
An element will undergo oxidation and form a positive ion on releasing one or more electrons from its valence shell. While reduction is occurred in a chemical reaction, then the element will be forming a negative ion with the acceptance of one or more electrons in its valence shell.
So in the given process of calcium fluoride, the one electron from the valence shell of calcium will be released making it as ions and this is termed as oxidation process. This one electron will be getting accepted by the fluorine ion and thus it will convert to
ions. This process of acceptance of electrons is termed as reduction.