The table compares the number of electrons in two unknown neutral atoms.
2 answers:
<u>Answer:</u>
<em>Option B is the Answer. </em>
<em>Both are highly reactive.</em>
<em></em>
<u>Explanation:</u>
For a neutral atom,
Atomic number = number of electrons = number of protons.
We can identify the element from its atomic number
It says 9 and 11 are the atomic number. By looking at the periodic table we know the elements are Fluorine and sodium.
Na has 2 electron in the first shell and 8 in the second and 1 in the outer shell
F has 2 electron in the first shell and 7 in the outer shell.
Atoms with less than 8 electrons in the outer shell are not stable. In order to attain stability atom either loses or gains or shares its electron and gets 8 electron in its outer shell to become more reactive.
Sodium easily loses its outer shell electron and becomes reactive
Na (2,8,1) becomes (2, 8)
Fluorine gains easily an electron and becomes reactive.
F (2, 7) becomes (2, 8)
Having 8 electrons in its outershell electron makes an atom more stable.
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Answer : The most likely happens during this reaction is, Oxidation-reduction
Explanation :
The balanced reaction will be,
In this reaction, neutral iron loses 3 electrons and oxidizes in (+3) state, and neutral oxygen gains 2 electrons and reduces in (-2) state,
When iron react with oxygen gas to give iron oxide. This process is known as iron rusting. During the reaction, oxidation-reduction process occurs.
Oxidation : It is a type of chemical reaction in which a substance loses its electrons. Or we can say that in oxidation, the oxidation number increases.
Reduction : It is a type of chemical reaction in which a substance gains its electrons. Or we can say that in reduction, the oxidation number decreases.
