Which substance is a primary source of hydrocarbons? A. cotton B. metals C. petroleum D. soil

Chemistry

2 answers:

Ivenika [448]3 years ago

5 0

C) petroleum is the right answer

Kazeer [188]3 years ago

5 0

c..............................

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What gets oxidized in a galvanic cell made with magnesium and zinc electrodes?

ankoles [38]

Answer: Magnesium

Explanation:

Galvanic cell is a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy.

The standard reduction potential for magnesium and zinc are as follows:

$E^0_{[Mg^{2+}/Mg]}= -2.37V$

$E^0_{[Zn^{2+}/Zn]}=-0.76V$

Reduction takes place easily if the standard reduction potential is higher (positive) and oxidation takes place easily if the standard reduction potential is less (more negative).

Here Mg undergoes oxidation by loss of electrons, thus act as anode. Zinc undergoes reduction by gain of electrons and thus act as cathode.

$Mg\rightarrow Mg^{2+}+2e^-$

$Zn^{2+}+2e^-\rightarrow Zn$

Thus magnesium gets oxidized.

4 0

2 years ago

Read 2 more answers

The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) ⇌ 2NO(g) Kc = 4.3 ×

Anuta_ua [19.1K]

Answer:

$Kc=~1.49x10^3^4}$

Explanation:

We have the reactions:

A: $N_2_(_g_) + O_2_(_g_) 2NO_(_g_)~~~~~~Kc = 4.3x10^-^2^5$

B: $2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~~~Kc = 6.4x10^9$

Our target reaction is:

$4NO_(_g_) N_2_(_g_) + 2NO_2_(_g_)$

We have $NO_(_g_)$ as a reactive in the target reaction and $NO_(_g_)$ is present in A reaction but in the products side. So we have to flip reaction A.

A: $2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}$

Then if we add reactions A and B we can obtain the target reaction, so:

A: $2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}$

B: $2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~Kc=6.4x10^9$

For the final Kc value, we have to keep in mind that when we have to add chemical reactions the total Kc value would be the multiplication of the Kc values in the previous reactions.

$4NO_(_g_) N_2_(_g_) + 2NO_2_(_g_)~~~Kc=\frac{6.4x10^9}{4.3x10^-^2^5}$