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3 years ago

Find the length of the unknown side. Round your answer to the nearest whole number.

Mathematics

2 answers:

Sav [38]3 years ago

8 0

Answer:

A. 7

Step-by-step explanation:

5^2+5^2=c62

25+25=c^2

50=c^2

7=c

Sliva [168]3 years ago

6 0

Answer:

Step-by-step explanation:

c=√a²+b²=√5²+5²≈7.07107

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62.1 divided by 58.6

Mrac [35]

Answer:

62.1/ 58.6= 1.05972696

the rounded answer would be 1.06

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Show work explain with formulas.

Sedaia [141]

Answer:

$\large\boxed{1.\ a_{44}=481,\ \sum\limits_{n=1}^\infty(11n-3),\ \text{the sum not exist}}$

$\large\boxed{3.\ \sum\limits_{n=1}^{47}(9n+16)=10,904}$

$\large\boxed{4.\ \sum\limits_{n=1}^\infty\bigg(6(2^n)\bigg),\ \text{the sum not exist}}$

Step-by-step explanation:

$1.\\8+19+30+41+...\\\\19-8=11\\30-19=11\\41-30=11\\\\\text{It's an arithmetic series.}\ a_1=8,\ d=11.\\\\\text{The formula for the n-th term of an arithmetic sequence:}\\\\a_n=a_1+(n-1)d\\\\\text{Substitute:}\\\\a_n=8+(n-1)(11)\qquad\text{use the distributive property}\ a(b-c)=ab-ac\\a_n=8+11n-11\\\boxed{a_n=11n-3}\\\\\text{Calculate the 44th term. Put n = 44 to the formula:}\\\\a_{44}=(11)(44)-3=484-3=481$

$\text{The summation notation:}\\\\\sum\limits_{n=1}^\infty(11n-3)\\\\\text{The sum not exist, because}\ d>1,\ \text{therefore}\ 11n-3\rightarrow\infty.$

=======================================================

$3.\\25+34+43+52+...+436\\\\34-25=9\\43-34=9\\52-43=9\\\\\text{It's an arithmetic series.}\ a_1=25,\ d=9.\\\\\text{The formula for the n-th term of an arithmetic sequence:}\\\\a_n=a_1+(n-1)d\\\\\text{Substitute:}\\\\a_n=25+(n-1)(9)\\a_n=25+9n-9\\a_n=9n+16\\\\\text{Calculate which the term of arithmetic series is the number 439.}\\\text{Put}\ a_n=439:\\\\9n+16=439\qquad\text{subtract 16 from both sides}\\9n=423\qquad\text{divide both sides by 9}\\n=47$

$\text{Therefore we have the series in summation notation:}\\\\\sum\limits_{n=1}^{47}(9n+16)\\\\\text{For calculation of the sum we use the formula of a sum of terms}\\\text{of an arithmetic sequence:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\text{Substitute}\ n=47,\ a_1=25,\ a_{47}=439:\\\\S_{47}=\dfrac{25+439}{2}\cdot47=\dfrac{464}{2}\cdot47=232\cdot47=10904\\\\\sum\limits_{n=1}^{47}(9n+16)=10,904$

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$4.\\12+24+48+...\\\\24:12=2\\48:24=2\\\\\text{It's\ a\ geometric series}\ a_1=12,\ r=2.\\\\\text{The formula for the n-th term of a geometic sequence:}\\\\a_n=a_1r^{n-1}\\\\\text{Substitute:}\\\\a_n=(12)(2^{n-1})\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\a_n=(12)\left(\dfrac{2^n}{2^1}\right)\\\\a_n=(6)(2^n)\\\\\text{The summation notation:}\\\\\sum\limits_{n=1}^\infty\bigg(6(2^n)\bigg)\\\\\text{The sum not exist, because}\ r>1,\ \text{therefore}\ 6(2^n)\to\infty$

6 0

3 years ago

Read 2 more answers

HELLLLLLLLLLLLLLLLLLLPPPPPPPP

jonny [76]

Answer:

option 4

Step-by-step explanation:

3 0

3 years ago

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Mark rolls 2 fair dice and adds the results from each.

Natali5045456 [20]

Answer:

P ( X > 5 ) = 72,2 %

Step-by-step explanation:

The probability of success ( outcomes bigger than 5 )

If dice 1 outcome is 6 no matter wich outcome we get from dice 2 all events are successful, the we have 6 outcomes

If dice 1 outcome is 5 we also have 6 outcomes

If dice 1 outcomes is 4 we have 5 positive outcomes

If dice 1 outcome is 3 we have 4 positive outcomes

If dice 1 outcome is 2 we have 3 positive outcomes

if dice 1 outcome is 1 we have 2 positive outcomes

Total evaluating dice 1: positive outcomes 26

We will get the sames results analysing dice 2 then we have a total of

52 successful events

And total numbers of outcomes is 36 + 36 = 72

Then

P ( X > 5 ) = 52/72

P ( X > 5 ) = 0,722

P ( X > 5 ) = 72,2 %

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3 years ago

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