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ValentinkaMS [17]
3 years ago
15

24 grams of magnesium metal reacts with 16 grams of oxygen gas to form magnesium oxide. according to the law of conservation of

mass, how much magnesium oxide will there be after the chemical change is complete?
Physics
1 answer:
wariber [46]3 years ago
8 0

The mass of magnesium oxide must be 40 grams

Explanation:

The law of conservation of mass states that the total mass of the reactant in a chemical reaction must be equal to the total mass of the products after the reaction has completed.

In this problem, we have:

Reactants:

Magnesium metal (mass: 24 grams)

Oxygen gas (mass: 16 grams)

Products:

Magnesium oxide (mass: ?)

According to the law of conservation of mass, the mass of the magnesium oxide must be equal to the sum of the mass of the magnesium metal and the oxygen gass. Therefore:

Mass (magnesium oxide) = 24 g + 16 g = 40 g

Learn more about law of conservation of mass:

brainly.com/question/5017646

#LearnwithBrainly

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The actual depth of a shallow pool 1.00 m deep is not the same as the apparent depth seen when you look straight down at the poo
DedPeter [7]

Answer:

d' = 75.1 cm

Explanation:

It is given that,

The actual depth of a shallow pool is, d = 1 m

We need to find the apparent depth of the water in the pool. Let it is equal to d'.

We know that the refractive index is also defined as the ratio of real depth to the apparent depth. Let the refractive index of water is 1.33. So,

n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{1\ m}{1.33}\\\\d'=0.751\ m

or

d' = 75.1 cm

So, the apparent depth is 75.1 cm.

4 0
3 years ago
Two conducting parallel plates 5.0 × 10−3 meter apart are charged with a 12-volt potential
photoshop1234 [79]

Answer: 2.4×10^-3 v/m

Explanation: distance between plates of capacitor (d) =5.0×10^-3m

Potential difference between plates (v) = 12v

Force on electronic charge (f) = 3.8×10^-16 N

Strength of electric field (E) =?

The formulae that relates potential difference, eoectiic field strength and distance between plates is given as

v = Ed

By substituting the parameters, we have that

12 = E × 5.0×10^-3

E = 12/ 5.0 × 10^-3

E = 2.4×10^-3 v/m

7 0
3 years ago
A rocket in deep space has an empty mass of 220 kg and exhausts the hot gases of burned fuel at 2500 m/s. What mass of fuel is n
Scilla [17]

Answer:

Explanation:

Let fuel is released at the rate of dm / dt where m is mass of the fuel

thrust created on rocket

= d ( mv ) / dt

= v dm / dt

this is equal to force created on the rocket

= 220 dv / dt

so applying newton's law

v dm / dt = 220 dv / dt

v dm = 220 dv

dv / v = dm / 220

integrating on both sides

∫ dv / v    = ∫ dm / 220

lnv =  ( m₂ - m₁ ) / 220

ln4000 - ln 2500 = ( m₂ - m₁ ) / 220

( m₂ - m₁ ) = 220 x ( ln4000 - ln 2500 )

( m₂ - m₁ ) = 220 x ( 8.29  - 7.82 )

= 103.4 kg .

8 0
4 years ago
Comparing Wave A (black) to Wave B (green), Wave A has a
Gennadij [26K]
I think it's C, longer wave length.
7 0
3 years ago
Read 2 more answers
Light is incident on the left face of an isosceles prism; with an apex angle of 49o, such that the light exiting the right face
Sunny_sXe [5.5K]

Answer:

\mu = 1.645

Explanation:

By Snell's law we know at the left surface

\theta_i = 19^o

\theta_r = ?

\mu_1 = 1

\mu_2 = \mu

now we have

1 sin19 = \mu sin\theta_r

0.33 = \mu sin\theta_r

now on the other surface we know that

angle of incidence = \theta_r'

\theta_e = 90

so again we have

\mu sin\theta_r' = 1 sin90

so we have

\theta_r = sin^{-1}\frac{0.33}{\mu}

\theta_r' = sin^{-1}\frac{1}{\mu}

also we know that

\theta_r + \theta_r' = 49

sin^{-1}\frac{0.33}{\mu} + sin^{-1}\frac{1}{\mu} = 49

By solving above equation we have

\mu = 1.645

3 0
3 years ago
Read 2 more answers
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